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Sergeeva-Olga [200]
3 years ago
5

A servey was conducted of 50 high school students, selected at random to find out how they travel to school. The table shows som

e results of the survey
Mathematics
1 answer:
DedPeter [7]3 years ago
5 0
I can help, but I need you to elaborate
You might be interested in
raph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the ci
andreyandreev [35.5K]

Answer:

Equation:

{x}^{2}   +  {y}^{2} +  2x  - 2y   -  35= 0

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )

Plug in the points to get:

( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )

( \frac{ -2}{2}, \frac{ 2}{2} )

(  - 1, 1)

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

r =  \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }

r =  \sqrt{ {(5 -  - 1)}^{2} + {( - 2- - 1)}^{2} }

r =  \sqrt{ {(6)}^{2} + {( - 1)}^{2} }

r =  \sqrt{ 36+ 1 }  =  \sqrt{37}

The equation of the circle is given by:

(x-h)^2 + (y-k)^2 =  {r}^{2}

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

(x- - 1)^2 + (y-1)^2 =  {( \sqrt{37}) }^{2}

(x + 1)^2 + (y - 1)^2 = 37

We expand to get:

{x}^{2}  + 2x  + 1 +  {y}^{2}  - 2y + 1 = 37

{x}^{2}   +  {y}^{2} +  2x  - 2y +2 - 37= 0

{x}^{2}   +  {y}^{2} +  2x  - 2y   -  35= 0

We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

{x}^{2}   +  {0}^{2} +  2x  - 2(0)  -   35= 0

{x}^{2}   +2x   -   35= 0

(x - 5)(x + 7) = 0

x = 5 \: or \: x =  - 7

The point (5,0) and (-7,0) lies on the circle.

When x=0

{0}^{2}   +  {y}^{2} +  2(0)  - 2y   -  35= 0

{y}^{2} - 2y   -  35= 0

(y - 7)(y + 5) = 0

y = 7 \: or \: y =  - 5

The point (0,-5) and (0,7) lie on this circle.

3 0
3 years ago
Plzz help me im giving 12 points
Serggg [28]
This Is very simple.

30m + 50 = 20m + 100

This is the new equation needed to solve for m.
first we must isolate "m".

30m + 50 = 20m + 100
        - 50             - 50

30m = 20m + 50
-20m   -20m

10m = 50

divide both sides by 10 to isolate "m".

m = 5

hope this helps!





3 0
3 years ago
8x+8(c+8)-6 show work its for my homework i get it but im just making sure i did it right:)
ioda
8x+8c+164-6
=8x+8c+158
7 0
3 years ago
Read 2 more answers
The intersection of lines y=-14x+3 and y=-32x+3 is .
Kamila [148]

The intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)

<h3>How to determine the intersection of the lines?</h3>

The lines are given as:

y = -14x + 3 and y = -32x+3

Substitute y = -32x+3 in

-32x+3 = -14x + 3

Evaluate the like terms

-18x = 0

Divide by -18

x = 0

Substitute x = 0 in y = -14x + 3

y = -14(0) + 3

Evaluate

y = 3

Hence, the intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)

Read more about linear equations at:

brainly.com/question/14323743

#SPJ1

6 0
2 years ago
A biking track has a length of 0.8 miles mi. How long is this in feet ft?
Sedbober [7]

Answer:

4224

Step-by-step explanation:

.8 mile = 4224 feet

8 0
3 years ago
Read 2 more answers
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