Answer:
Step-by-step explanation:
The given triangle is a right angled triangle.
So, the angles in the triangle are :
Solving according to <u>angle sum property</u>,
Sum of all angles in a triangle is 180°
90° + (2x + 38)° + (5x - 11)° = 180°
117° + 7x = 180°
7x = 180° - 117°
7x = 63°
x = 9
Angles =
2(9) + 38
56°
5(9) - 11
34°
The angles are 56°, 90° and 34°.
Answer:
15<em>y</em> = -28 <em>x</em> + 205.
Step-by-step explanation:
Slope intercept form of equation is <em>y = mx + c</em> where m is slope and c is the y intercept.
Now slope of line passing through points (-5, 23) and (10, -5):
Now equation of line:
<em> y = mx + c</em>
substituting the value of m in above expression,
Now, since the line is passing through the point (-5, 23) therefore, x = -5 and y = 23. By substituting these values in above equation,
So equation of line in slope intercept form:
Further solving,
15<em>y</em> = -28 <em>x</em> + 205.
Answer:
The correct option is;
∠A ≅ ∠X
Step-by-step explanation:
The given coordinates of the points of triangle ACB are;
A(-4, 4), C(-1, 3), B(-4, 0)
The given coordinates of the points of triangle XYZ are;
X(0, 8), Y(8, 8), Z(6, 2), therefore, we have
The length. l. of segment is given by the following formula;
For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)
For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4
For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2
For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8
For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2
For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10
Therefore;
XY ~ AB, XZ ~ BC, ZY ~ AC
Which gives;
∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z
