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Vikentia [17]
3 years ago
7

Jayla bought 20 candies for 10 dollars. What is the unit price dollars per candy?

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
5 0

Answer:

$1.00

Step-by-step explanation:

20/10=2

Dahasolnce [82]3 years ago
5 0

Answer:

$2 per candy

Step-by-step explanation:

20 \ 10 = 2

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3 Caleb claims that when you multiply a number by 10, you can just write a 0 at the right end of the number. Caleb gives the exa
devlian [24]

Answer:

They are both correct

Step-by-step explanation:

It's interpretation of the concept. In common practice multiplying by 10 means you add a zero and that's what we teach 10 year olds. But what does adding a zero mean? It means adding a place value and that's what you learn when you are

So in both examples just add a decimal:

2.0 x 10 = 20.

0.2 x 10 = 2.0

In conclusion, it depends on the level of precision required in the discussion and the level of maturity as to who is correct in their examples. If you are teaching 3rd graders math, by all means you add a zero. If you are discussing physics you are shifting over a place value.

8 0
3 years ago
Layla has 5.49 pounds of wood she divides it into 7 <br> so basically 5.49÷7
Nuetrik [128]

Answer:

0.7842857142857143

Step-by-step explanation: i would right an explanation but i cant put it all so you will just have to trust me

7 0
2 years ago
How do you solve m/9 divided by mn squared / 3
ivolga24 [154]
\frac{m}{9}:\frac{mn^2}{3} =\frac{m}{9} \cdot \frac{3}{mn^2} =\frac{1}{3n^2}


3 0
3 years ago
Read 2 more answers
Solve the system of equations 2r + 2s = 50 and 2r – s = 17.
WARRIOR [948]
Eq1) 2r+2s=50
eq2) 2r-s=17

solve for s in equation2 (eq2)

-s=17-2r
s=-17+2r
Substitute s into equation1 (eq1)
2r+2(-17+2r)=50
2r-34+4r=50
6r-34=50
6r=50+34
6r=84
r=14
Substitute into either equation and solve for s
2(14)-s=17
28-s=17
-s=17-28
-s=-11
s=11
6 0
3 years ago
2(4x+1)&lt;3(2x-3) solve the inequality
Anestetic [448]

Answer:

x< -11/2

Step-by-step explanation:

Let's solve your inequality step-by-step.

2(4x+1)<3(2x−3)

Step 1: Simplify both sides of the inequality.

8x+2<6x−9

Step 2: Subtract 6x from both sides.

8x+2−6x<6x−9−6x

2x+2<−9

Step 3: Subtract 2 from both sides.

2x+2−2<−9−2

2x<−11

Step 4: Divide both sides by 2.

2x/2<−11/2

x< −11/2

4 0
3 years ago
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