Answer:
7.1 weeks to 68.4 weeks
Step-by-step explanation:
Chebyshev's Theorem states that:
75% of the measures are within 2 standard deviations of the mean.
89% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 38.1
Standard deviation = 10.1
Between what two search times does Chebyshev's Theorem guarantee that we will find at least 89% of the graduates
Between 3 standard deviations of the mean.
So from 38.1 - 3*10.1 = 7.8 weeks to 38.1 + 3*10.1 = 68.4 weeks
If you go on my profile you will see a similar problem that I already answered today.
Lets start by using a formula (don't remember the name)
(y-y1)=M(x-x1)
M is slope and y is first y value and y1 is second y value same applies to X.
Substitute in the values.
(5-q) = 10(-6-(-7))
5-q = 10*(1)
5-q = 10
-q = 5
q = -5
Check:
Substitute in the value of "q" and use the formula to find slope:
(y1-y)/(x1-x)
Substitute
(-5-5)/(-7-(-6))
-10/-1
10
Your Answer:
The value of "q" is -5
If you need help simplifying this equation then the answer is ... -12s-15
Answer:
The number of big pictures are 49 and number of small pictures are 48 .
Step-by-step explanation:
Let us assume that the number of big pictures are x .
Let us assume that the number of small pictures are y .
As given
Big pictures are 56$ each small ones are 34$.
97 were sold at the total of $4,376.
Equations becomes
x + y = 97
56x + 34y = 4376
Multiply x + y = 97 by 56 and subtracted from 56x + 34y = 4376 .
56x - 56x + 34y - 56y = 4376 - 5432
-22y = - 1056
22y = 1056
y = 48
Put value of y in the equation x + y = 97
x + 48 =97
x = 97 - 48
x = 49
Therefore the number of big pictures are 49 and number of small pictures are 48 .