Answer:
h(x + 1) = (x+3)(x-1)
Step-by-step explanation:
Simply plug the value of x+1 into the equation for x.
h(x) = x^2 - 4
h(x + 1) = (x + 1)^2 - 4
h(x + 1) = x^2 + 2x + 1 - 4
h(x + 1) = x^2 + 2x - 3
h(x + 1) = (x+3)(x-1)
Cheers.
For all real constants <span>aa</span> and <span>bb</span> such that <span><span>a>1</span><span>a>1</span></span>,
<span><span><span>lim<span>n→∞</span></span><span><span>nb</span><span>an</span></span>=0</span></span>
Answer:
11.968
Step-by-step explanation:
