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Firlakuza [10]
3 years ago
10

A room contains 5 cats and 2 dogs if the ratio is 5 to 2 the rate can be expressed as 5 cats 2 dogs

Mathematics
1 answer:
kap26 [50]3 years ago
5 0
What's the question being asked here?
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Resistors for electronic circuits are manufactured on a high-speed automated machine. The machine is set up to produce a large r
Anettt [7]

Answer:

See explanation

Step-by-step explanation:

Given

See attachment for proper presentation of question

Required

Mean and Range

To do this, we simply calculate the mean and the range of each row.

\bar x = \frac{\sum x}{n} ---- mean

Where:

n = 4 ---- number of rows

R = Highest - Lowest --- range

So, we have:

Sample 1

\bar x_1 = \frac{1027+ 994 +977 +994 }{4}

\bar x_1 = 998

R_1 = 1027- 994

R_1 = 33

Sample 2

\bar x_2 = \frac{975 +1013 +999 +1017}{4}

\bar x_2 = 1001

R_2 =  1017 - 975

R_2 = 42

Sample 3

\bar x_3 = \frac{988 +1016 +974 +997}{4}

\bar x_3 = 993.75

R_3 = 1016-974

R_3 = 42

Sample 4

\bar x_4 = \frac{998 +1024 +1006 +1010}{4}

\bar x_4 = 1009.5

R_4 = 1024 -998

R_4 = 26

Sample 5

\bar x_5 = \frac{990 +1012 +990 +1000}{4}

\bar x_5 = 998

R_5 = 1012 -990

R_5 = 22

Sample 6

\bar x_6= \frac{1016 + 998 +1001 +1030}{4}

\bar x_6= 1011.25

R_6= 1030-998

R_6= 32

Sample 7

\bar x_7 = \frac{1000 +983 +979 +971}{4}

\bar x_7 = 983.25

R_7 = 1000-971

R_7 = 29

Sample 8

\bar x_8 = \frac{973 +982 +975 +1030}{4}

\bar x_8 = 990

R_8 = 1030-973

R_8 = 57

Sample 9

\bar x_9 = \frac{992 +1028 +991 +998}{4}

\bar x_9 = 1002.25

R_9 = 1028 -991

R_9 = 37

Sample 10

\bar x_{10} = \frac{997 +1026 +972 +1021}{4}

\bar x_{10} = 1004

R_{10} = 1026 -972

R_{10} = 54

Sample 11

\bar x_{11} = \frac{990 +1021 +1028 +992}{4}

\bar x_{11} = 1007.75

R_{11} = 1028 -990

R_{11} = 38

Sample 12

\bar x_{12} = \frac{1021 +998 +996 +970}{4}

\bar x_{12} = 996.25

R_{12} = 1021 -970

R_{12} = 51

Sample 13

\bar x_{13} = \frac{1027 +993 +996 +996}{4}

\bar x_{13} = 1003

R_{13} =1027 -993

R_{13} =34

Sample 14

\bar x_{14} = \frac{1022 +981 +1014 +983}{4}

\bar x_{14} = 1000

R_{14} = 1022 -981

R_{14} = 41

Sample 15

\bar x_{15} = \frac{977 +993 +986 +983}{4}

\bar x_{15} = 984.75

R_{15} = 993-977

R_{15} = 16

8 0
3 years ago
Here is a pattern of dots.
EleoNora [17]

The dots in the patterns are illustrations of a sequence or progression

  • The number of dots in step 10 is 84
  • The number of dots in step n is (n -1)^2+ 3

<h3>The number of dots in step 10</h3>

From the pattern, we have:

  • Step 0 = 3 dots
  • Step 1 = 4 dots
  • Step 2 = 7 dots
  • Step 3 = 12 dots

So, we have the following pattern

T_n = (n -1)^2+ 3

When n = 10, we have:

T_{10} = (10 -1)^2+ 3

T10 = 84

This means that, there will be 84 dots in step 10 and there will be (n -1)^2+ 3 dots in step n

Read more about sequence at:

brainly.com/question/7882626

3 0
2 years ago
How many millimeters are in 170 centimeters
Vladimir [108]

There are 10millimeters in one centimeter.

Since centimeter is a bigger measurement you'd multiply.

170 * 10 = 1700

There are 1700 millimeters in 170cm

Answer

1700 millimeters

3 0
3 years ago
What is the decimal number of 100/2​
Marina86 [1]
I think it might be 50? unless you meant 2/100, which is 0.02
4 0
2 years ago
Fred works as a gardener. He charges at least $15 to drive to a residence and
Amanda [17]

We are required to find an inequality which best represents the relationship between the number of hours gardening g and the total charge c

The inequality which best represents the relationship between the number of hours gardening g and the total charge c is c ≥ 15 + 12g

At least means greater than or equal to (≥)

fixed charge = $15

charges per hour = $12

Total charge = c

Number of hours = g

The inequality:

<em>Total charge ≥ fixed charge + (charges per hour × Number of hours</em>

c ≥ 15 + (12 × g)

c ≥ 15 + (12g)

c ≥ 15 + 12g

Therefore, the inequality which best represents the relationship between the number of hours gardening g and the total charge c is c ≥ 15 + 12g

Read more:

brainly.com/question/11067755

7 0
3 years ago
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