Unusual notation. I won't fuss with it.
a. We have isosceles PRT, so angle RPT = angle RTP.
By the definition of angle bisector, angle MTP = angle MTF, and angle MPT = angle MPU.
We have m angle RTP = m angle MTF + m angle MTP = 2 m angle MTP
Similarly, m angle RPT = 2 m angle MPT
2 m angle MTP = 2 m angle MPT
angle MPT = angle MPT
That's the first part.
b. That makes MPT isosceles.
c. 2x+124=180
2x = 56
x = 28 degrees
MTP = 28 degrees
d. We have angle RPT=angle RTP=56 so PRT=180-2(56)=68 degrees
PUT = 180 - UTP - UPT = 180 - 28 - 56 = 96 degrees
Bad drawing, PUT looks acute.
angle PRT = 68 degrees, angle PUT = 96 degrees
3. It has 3 symmetrical lines, so, therefore, has 3 lines of reflectional symmetry.
Hope this helps!
<em>~cupcake </em>
Answer:
1 solution
Step-by-step explanation:
Jeremy can simplify the equation enough to determine if the x-coefficient on one side of the equation is the same or different from the x-coefficient on the other side. Here, that simplification is ...
-3x -3 +3x = -3x +3 +3
We see that the x-coefficient on the left is 0; on the right, it is -3. These values are different, so there is one solution.
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In the attached, the left-side expression is called y1; the right-side expression is called y2. The two expressions are equal where the lines they represent intersect. That point of intersection is x=3. (For that value of x, both sides of the equation have a value of -3.)
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<em>Additional comment</em>
If the equation's x-coefficients were the same, we'd have to look at the constants. If they're the same, there are an infinite number of solutions. If they are different, there are no solutions.
Answer:
I would like to say 20 but I'm not sure
Answer:
Step-by-step explanation:
Find the equation of the segment going from (0,-5) to (3,7)
y intercept = -5
Slope = (-5 - 7) / (0 - 3) = -12/-3 = 4
equation: y = 4x - 5
g(x) = x^2 / f(x)
f(x)= (4x - 5)
g(x) = x^2 / (4x - 5)
g'(x) = x^2 * (4x - 5)^-1
g'(x) = 2x*(4x - 5)^-1 + (-1) *4* x^2 (4x - 5)^-2
I will leave that monster the way it is and just find g'(1)
g'(1) = 2(1) * (4(1) - 5)^-1 + (-1) (1)^2 *4* (4(1) - 5)^-2
g'(1) = 2(1) * (-1)^-1 + (-1) (1)^2 *4 * (-1)^2
g'(1) = -2 + (-1) (1)^2 (4)
g'(1) = - 2 + (-1) (1)^2 (4)
g'(1) = - 2 - 4
g'(1) = - 6
