One worker<span> produces an average of 84 units per </span>day<span> with a street </span>What is the probability<span> that in any </span>single day worker 1 will outproduce worker 2<span>? A) 0.1141.
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Answer, factory worker productivity<span> is </span>normally distributed<span>. </span>One worker produces<span> an </span>average<span> of 75 </span>units per day<span> with a standar, day with a </span>standard deviation<span> of 20. </span>Another worker produces<span> at an </span>average rate<span> of 65 </span><span>per day.
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40 mins left! total time= 60 mins x 3 hours =180 mins. 180 divided by 9 is 20. 20 times 7 is 140. 180-140 equals 40. yay!
We are given : m∠WYX=(2x−1)° and m∠WYZ=(4x+1)°.
∠WYX and ∠WYZ are complementary.
We know, sum of complementary angles is = 90°.
So, we need to add ∠WYX and ∠WYZ and set it equal to 90°.
m∠WYX + m∠WYZ = 90°.
Plugging values of ∠WYX and ∠WYZ in the above equation, we get
(2x−1)° + (4x+1)° = 90°.
Removing parentheses from both sides,
2x-1 + 4x+1 =90.
Combining like terms,
2x+4x= 6x and -1+1 =0
6x +0 =90.
6x=90.
Dividing both sides by 6.
6x/6 =90/6
x= 15.
Plugging value of x=15.
m∠WYX=(2x−1)° = 2*15 -1 = 30 -1 =29
m∠WYZ=(4x+1)° = 4*15 +1 = 60+1 = 61.
Therefore, ∠WYX=29° and ∠WYZ=61°.
