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3 years ago

(10x-23) how do i find x with 106 as an arc

Mathematics

2 answers:

emmasim [6.3K]3 years ago

5 0

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xenn [34]3 years ago

3 0

If we connect A to D and continue the line up to the circle than
AngBAD=angDAC
10x-23=106/2
10x=53+23
x=7.6

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Jeremy has $1200 in spending money for the fall semester of college. He needs to purchase car insurance at $120 for 4 months, $2

abruzzese [7]

Answer:

Jeremy Will have more than just $200 to spend on Christmas presents.

Explanation :

He has a total of $1200.

He spends a $120 for car insurance. (1)

He needs to spend $25 a week for lunch. He has to do this for 16 weeks so 25*16 = $400. (2)

He needs to spend $20 a week for entertainment. For 16 weeks that'll be 20*16 = $320 (3)

adding (1) (2) and (3)

We get Jeremy's total spending will be $840. Jeremy has $1200.

1200-840 = $360

So Jeremy will have $360 to spend on Christmas present.

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3 years ago

What linear function can be represented by the set of ordered pairs?

zzz [600]

Solving for the slope using points ( (−4, 15), (0, 5)
M = ( 15 – 5) / ( -4 – 0) = -5 / 2
Solving for b 
Y = mx + b 5 = 0(-5/2) + b
B = 5
So the linear function is
Y = (-5/2) x + 5

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3 years ago

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If Sarah is 24 years younger than her mother and if the sum of their ages is 68, how old is Sarah?

irina [24]

Use subtraction the answer is 44

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4 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

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3 years ago

The___ of an angle is the ratio of the opposite leg length to the hypotenuse length.

ozzi

The answer would be sine

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3 years ago

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