Answer:
The area of the shaded portion of the figure is
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The shaded area is equal to the area of the square less the area not shaded.
There are 4 "not shaded" regions.
step 1
Find the area of square ABCD
The area of square is equal to

where
b is the length side of the square
we have

substitute

step 2
We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):
The area of circle is equal to

The diameter of the circle is equal to the length side of the square
so
---> radius is half the diameter
substitute


Therefore, the area of 2 "not-shaded" regions is:

and the area of 4 "not-shaded" regions is:

step 3
Find the area of the shaded region
Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:
so
---> exact value
assume

substitute
When x = -3 y = -5
When x = -1 y = -1
When x = 0 y = 1
When x = 2 y = 5
Three of the points that are on the graph are
- (-1.38,2.05)= y=11+5x/2
- (0,5.5)= y-intercept, (0,11/2)
- (-2.2,0)= x-intercept, (-11/5,0)
Answer:
a) y-intercept = 17; initial design strength percentage
b) slope = 2.8; increase in that percentage each day
c) 29.6 days to 100% design strength
Step-by-step explanation:
a, b) The equation is in the form called "slope-intercept form."
y = mx + b
where the slope is m, and the y-intercept is b.
Your equation has a slope of 2.8 and a y-intercept of 17.
The y-intercept is the percentage of design strength reached 0 days after the concrete is poured. The strength of the concrete when poured is 17% of its design strength.
The slope is the percentage of design strength added each day after the concrete is poured. The concrete increases its strength by 2.8% of its design strength each day after it is poured.
__
c) To find when 100% of design strength is reached, we need to solve for x:
100 = 2.8x +17
83 = 2.8x
83/2.8 = x ≈ 29.6
The concrete will reach 100 percent of its design strength in about 30 days.
The correct answer for this question is this one: "B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power"
<span>A. 5 times the quotient 5 cubed over two-fifths, raised to the second power
B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power
C. 5 to the negative 2 over 5 to the negative 5
E. 5 times the quotient 5 to the 5 over 5 cubed</span>