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myrzilka [38]
3 years ago
7

Two solid cubes have the same Mass but their edges are in the ratio of 4:1. What isthe ratio of their densities?​

Physics
1 answer:
lawyer [7]3 years ago
7 0

Let <em>m</em> be the mass of both cubes. If the smaller cube has side length <em>x</em>, then its volume is <em>x</em> ³. The side lengths of the larger cube have length 4<em>x</em>, so the larger cube's volume is (4<em>x</em>)³ = 64<em>x</em> ³, or 64 times as large as the smaller cube.

The first cube has a density of <em>m</em>/<em>x</em> ³, while the larger one has a density of <em>m</em>/(64<em>x</em> ³) = 1/64 <em>m</em>/<em>x</em> ³, so the ratio of densities is (1/64):1, or 1:64 (larger cube to smaller cube).

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Which of the following is true of salt lakes?
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3 0
4 years ago
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(8%) Problem 3: Sound in water travels at a velocity governed by the relation v = √(B/rho) where B is the bulk modulus and rho i
Fittoniya [83]

Answer:

the time required for the sound to travel between the whales 0.66 S.

Explanation:

As given in the problem, the velocity of sound wave (v) is governed by the equation

v = \sqrt{\dfrac{B}{\rho}}

Given, B = 2.38 \times 10^{9} Pa and \rho = 1046 Kg m^{-3}

So for salt water, the velocity of sound wave (v_{s}) can be written as

v_{s} = \sqrt{\dfrac{2.38 \times 10^{9}}{1046}} ms^{-1} = 1.508 \times 10^{3} ms^{-1}

As the whales are d = 1 Km or 1000 m apart from each other, so the time (t) required for the sound wave to travel this distance is given by

t = \dfrac{d}{v_{s}} = \dfrac{1000 m}{1.508 \times 10^{3}} = 0.66 s

5 0
3 years ago
The plane flight covers 400 miles in the first hour. As you approach the landing site, it takes you an hour to cover the last 20
9966 [12]
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3 0
4 years ago
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Both a fire blanket and the spray from a fire extinguisher put out a fire by pressing down on the fire and pushing any oxygen aw
Sladkaya [172]

Answer:

Water can carry electricity

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7 0
4 years ago
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When the starter motor on a car is engaged, there is a 300 A cunent in the wires between the bauery and the motor. Suppose the w
docker41 [41]

Answer:

diameter of transmission is 3.473 mm

Explanation:

given data

current = 300 A

total wire length = 1.0 m

voltage drop = 0.55 V

solution

as here Resistivity of copper is = 1.68 × 10^{-8} ohm- m

so we get here resistance of wire that is

resistance = \frac{V}{I}    ..............1

R = \frac{0.55}{310}  

R = 1.774 × 10^{-3}  ohm

and now we get diameter of wire that is

R = \frac{\rho l}{A}    .............2

\pi \frac{d^2}{4} = \frac{\rho l}{R}    

d² = \frac{4\rho l}{\pi R}     ...............3

put here value

d² = \frac{4\times 1.68\times 10^{-8} \times 1}{\pi \times 1.774\times 10^{-3}}  

d = \sqrt{12.064\times 10^{-6}}

d = 3.473 × 10^{-3} m

d = 3.473 mm

so diameter of transmission is 3.473 mm

4 0
4 years ago
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