Q = magnitude of charge on each of the two point charge = 3.60 mC = 3.60 x 10⁻³ C
r = distance between the two point charges = 9.3 cm = 0.093 m
k = constant = 9 x 10⁹ Nm²/C²
F = magnitude of the force between the two point charges = ?
according to coulomb's law , force between two charges is given as
F = k Q²/r²
inserting the values
F = (9 x 10⁹) (3.60 x 10⁻³)²/(0.093)²
F = 1.35 x 10⁷ N
Answer:
Explanation:
We are asked to find the acceleration of a box.
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
The mass of the box is 5 kilograms. There are two forces applied: a 25 Newton force and a 50 Newton force, both applied right. Since they are applied in the same direction, we can add them.
- 25 N right + 50 N right = 75 N right.
Now we know 2 of the variables in the formula:
- F= 75 N or 75 kg*m/s²
- m= 5 kg
Substitute the values into the formula.
We are solving for a, so we must isolate the variable. It is being multiplied by 5 kilograms. The inverse operation of multiplication is division. Divide both sides by 5 kg.
The units of kilograms cancel.
The acceleration is in the same direction as the force, so the acceleration is <u> 15 meters per second squared to the right.</u>
In California, changing lanes in the middle of an intersection D. is legal.
Although it is legal, it's not necessarily the safest thing to do in an intersection.
Let T be period
f=1/T
f=1/0.25
f=4hz