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tino4ka555 [31]
3 years ago
13

An alert physics student stands beside the tracks as a train rolls slowly past. He notes that the frequency of the train whistle

is 452 Hz when the train is approaching him and 442 Hz when the train is receding from him. Using these frequencies, he calculates the speed of the train. What value does he find
Physics
1 answer:
Dovator [93]3 years ago
4 0

Answer:The velocity of the train is 3.84m/s

Explanation:

According to the Doppler effect, if the source is moving towards you then the apparent frequency of the sound emitted by the source is higher and if the source is moving away from you then the apparent frequency of the sound emitted by the source is smaller.

This is given by:

fo = V +-Vo/ V +-Vo × source

Where fo= observed frequency

V= velocity of sound

Vo= vo it of the observer

fsource= frequency the source

Given:

Observed frequency of the approaching train fo1= 452Hz

The observed frequency of train= fo2= 442Hz

Velocity of sound= 334m/s

Velocity of source=?

Train approaching the observer is given by:

fo1= V/(V - Vs)× source ...eq1

Train passes the student is given by:

fo2= V/(V - Vs)×source ...eq2

Divide eq1 by eq2

452/442 = (343+Vs)/(343 - Vs)

1.02 =(343+Vs)/(343 -Vs)

Cross multiply

1.02(343- Vs) = 343 + Vs

350.76 - 1.02Vs = 343 + Vs

Collecting like terms

350.76 -343= 1.02Vs+ Vs

7.76 = 2.02Vs

Vs= 7.76/2.02

Vs= 3.84m/s

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A vibrating pendulum makes 20 complete vibrations in 12.2 seconds. Determine the vibrational period of the pendulum, along with
Hitman42 [59]

Answer:

And the same can be said of a pendulum vibrating about a fixed position or of a guitar ... along the time axis, it is possible to determine the time for one complete cycle. ... It takes 2.3 seconds to complete the first full cycle of vibration. ... Since the standard metric unit of time is the second, frequency has units of cycles/second.

Explanation:

Plz mark brainliest im only 12. and i have never been marked brainliest.

4 0
3 years ago
A 0.700-kg particle has a speed of 1.90 m/s at point circled A and kinetic energy of 7.20 J at point circled B. (a) What is its
Savatey [412]

Answer:

a). E_{kA}=1.2635 J

b). V_{B}=4.535\frac{m}{s}

c). ΔE_{t}=8.4635 J

Explanation:

ΔE=kinetic energy

a).

E_{kA}=\frac{1}{2}*m*v_{A} ^{2} \\ v_{A}=1.9 \frac{m}{s}\\ m=0.70kg\\E_{kA}=\frac{1}{2}*0.70kg*(1.9 \frac{m}{s})^{2} \\E_{kA}=1.2635 J

b).

E_{kB}=\frac{1}{2}*m*v_{B} ^{2}

V_{B}^{2}=\frac{E_{kB}*2}{m} \\V_{B}=\sqrt{\frac{E_{kB}*2}{m}} \\V_{B}=\sqrt{\frac{7.2J*2}{0.70kg}} \\V_{B}=4.53 \frac{m}{s}

c).

net work= EkA+EkB

E_{t}=E_{kA}+ E_{kB}\\E_{t}=1.2635J+7.2J\\E_{t}=8.4635J

3 0
3 years ago
a tms (transcranial magnetic stimulation) device creates very rapidly changing magnetic fields. the field near a typical pulsed-
Digiron [165]

Part A : 4.33 Volt.

Part B : 4764 Amperes.

Given Data :  

Field near a typical pulsed-field machine rises from 0 T to 2.5 T in 200 μs.

Axis of his 2.1-cm-diameter wedding band is parallel to the field.

Part A :

induced emf = rate of change of magnetic flux

= d (B A )/dt

= A dB/dt

= { π (2.1 x 10^-2 / 2)^2) (2.5) } / (200 x 10^-6)

E = 4.33 Volt

Part B :

R = rho L / A

R = { (6.2 x 10^-8) ( π x 0.021) } / (4.5 x 10^-6)

R = 9.10 x 10^-4 Ohm

We know, (I = V/ R)

I = 4.33 Volts / 9.10 x 10^-4 Ohm

I = 4764 Amperes

What exactly is the function of TMS?

Transcranial magnetic stimulation (TMS) is a noninvasive procedure that uses magnetic fields to stimulate nerve cells in the brain to alleviate depression symptoms. TMS is usually used when other depression treatments have failed.

Find more on TMS at : brainly.com/question/13851741

#SPJ4

➤ Although your question isn't complete, I may have assumed that you were referring to this specific question.

The complete question is :

A TMS (transcranial magnetic stimulation) device creates very rapidly changing magnetic fields. The field near a typical pulsed-field machine rises from 0 T to 2.5 T in 200 μs. Suppose a technician holds his hand near the device so that the axis of his 2.1-cm-diameter wedding band is parallel to the field.

Part A: What emf is induced in the ring as the field changes? Express your answer to two significant figure E= ___ unit_

Part B: If the band is made of a gold alloy with resistivity 6.2×10−8Ω⋅m and has a cross-section area 4.5 mm2 , what is the induced current? Express your answer to two significant figures and include the appropriate units. I= ___ units__

6 0
2 years ago
Refrigerant-134a enters the expansion valve of a refrigeration system at 160 psia as a saturated liquid and leaves at 30 psia. D
KatRina [158]

Answer:

Temperature : 92.9 F

Internal Energy change: -2.53 Btu/lbm

Explanation:

As

mh1=mh2

h1=h2

In table A-11 through 13E

p2=120Psi, h1= 41.79 Btu/lbm,

u1=41.49

So T1=90.49 F

P2=20Psi

h2=h1= 41.79 Btu/lbm

T2= -2.43F

u2= 38.96 Btu/lbm

T2-T1 = 92.9 F

u2-u1 = -2.53 Btu/lbm

3 0
3 years ago
This is a form of energy representing the motion of the molecules which make up an object. A. Thermal Energy B. Kinetic Energy C
bija089 [108]

Answer:

Kinetic energy.

Explanation:

  • There are many kinds of energy. Some of them are kinetic energy, potential energy, thermal energy etc.
  • The energy that shows the motion of the object is called its kinetic energy.
  • Also, the sum of kinetic energy and the gravitational potential energy is called mechanical energy.
  • Out of the given options, kinetic energy is the form of energy that represents the motion of the molecules which make up an object.
  • Hence, the correct option is (B).
4 0
3 years ago
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