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Sav [38]
3 years ago
5

A photon with a frequency of 5.48 × 10^14 hertz is emitted when an electron in a

Physics
1 answer:
mezya [45]3 years ago
4 0
     Using the Planck's Equation, comes:

E=hf \\ E=6.63*10^{-34}*5.48*10^{14}*J \\ \boxed {E=36.3324*10^{-20}*J}

If you notice any mistake in my english, please let me know, because i am not native.
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The total electric flux from a cubical box 26.0 cm on a side is 1840 N m2/C. What charge is enclosed by the box?
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The expression of the electric flux is

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Here,

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\epsilon_0 = Permittivity due to free space

Rearranging to find the charge,

Q = \epsilon_0 \Phi

Replacing with our values we have finally

Q = (8.85*10^{-12}F\cdot m^{-1})(1.84*10^3 N\cdot m^2/C)

Q = 1.6284*10^{-8} C (\frac{10^9nC}{1C})

Q = 0.1684nC

The charge enclosed by the box is 0.1684nC

The sign of the charge can be decided by using the direction of the flux. The charge enclosed by the cube can be calculated by using the electric flux and the permitivity of free space.

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In his psychology class, Professor Adams said that fear of spiders and snakes are common in humans, but fear of automobiles is n
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Answer:

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