Gavin thinks the equation P = 3 × 4 could be used to find the perimeter for two different

Mathematics

1 answer:

kondaur [170]3 years ago

5 0

This shape is a Rectangle because the sides aren’t even

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HELP DUE IN 10 MINS!

Alenkasestr [34]

Answer:

x= 55°

y=70°

z= 35°

Step-by-step explanation:

.................

7 0

3 years ago

Read 2 more answers

What would go on the x axis and what would go on the y axis, I can do the graphing.

Ilia_Sergeevich [38]

The x-axis shows the independent variable and the y-axis shows the dependent variable. so therefore the x-axis will be the years and the y-axis will be the subscribers. hope this helped!

6 0

4 years ago

RIGHT ANSWER GETS BRAINLIEST NO LINKS Factor the square root.<br> √160

kipiarov [429]

Answer:

<h2>Factor perfect squares out of the square root until there are no more perfect squares inside.</h2>

Step-by-step explanation:

<h2>Begin by working inside the square root itself. You can manipulate the interior of the square root as much as you'd like so long as you don't violate any other rules of algebra. </h2>

<h2>Because 16 is a perfect square, we can pull it out of the square root as a 4.</h2>

<h2>That will simplify down to 4√10</h2>

<h2>because there are no additional perfect square factors in 10, the resultant is simplified.</h2>

<h2>Therefore, √160 simplifies to 4√10</h2>

3 0

3 years ago

There are 255 students this term completing this same assignment. Assuming they calculated the CI correctly, how many students s

andrey2020 [161]

Answer:

The number of students we expect to have an interval that does not contain the true mean value is, $255\times [\alpha\%]$ .

Step-by-step explanation:

A [100(1 - α)%] confidence interval for true parameter implies that if 100 confidence intervals are created then [100(1 - α)] of these 100 confidence intervals will consist the true population parameter value.

Here α is the significance level. It is defined as the probability rejecting the claim that the true parameter value is not included in the 100(1 - α)% confidence interval.

It is provided that 255 students create the same confidence interval, correctly.

Then the number of students we expect to have an interval that does not contain the true mean value is, $255\times [\alpha\%]$

For instance, if the students are creating a 95% confidence interval for mean then the number of students we expect to have an interval that does not contain the true mean will be:

The significance level is:

$Confidence\ level=100(1-\alpha)\\\frac{95}{100}=(1-\alpha)\\\alpha =1-0.95=0.05$