Help me please
TexFormula1" title="f(x) = ln(x { } ^{2} + 2 ) " alt="f(x) = ln(x { } ^{2} + 2 ) " align="absmiddle" class="latex-formula">
1 answer:
➡Answer: x=√(e^y-2)
❇Explanation:
Step1: Let f(x)=y,then
↪y=ln(x²+2)
Step2: Converting it into exponential form,
↪e^y=x²+2
↪x²=e^y-2
Step3: Taking square root of both sides,
↪x=√(e^y-2)
❇Note:
ln means log with base e.
So in step 2 , base e of ln (x²+2) goes to other side in the form e^y. That is simply the property of log I used there..
Hope this helps!
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