The standard equation for an ellipse is

where
(h,k) = coordinates of the center
a, b = semi-major and semi-minor axes
Refer to the figure shown below.
The center of the ellipse is at (0,0).
Therefore, h=0, k=0.
One focus is at (12, 0)
Therefore
c = 12
One directrix is at 14 1/12 = 169/12.
Because the directrix is located at x = a²/c, therefore
a²/12 = 169/12
a² = 169/144
a = 13
Because c² = a² - b², obtain
b² = a² - c²
= 169 - 144 = 25
b = 5
Answer:
The equation for the ellipse is
Answer:
1. 16
2. -4
Step-by-step explanation:
First factor the expression
lim x→1 (x^3 + 5x^2 + 3x-9)/(x-1)
lim x→1 (x-1) (x+3)^2/(x-1)
Canceling the x-1 in the top and bottom
lim x→1 (x+3)^2
Let x=1
lim x→1 (1+3)^2 = 4^2 = 16
2. lim x→0 (x^2 -6x+8) /(x-2)
First factor the expression
lim x→0 (x-4) (x-2) /(x-2)
Canceling the x-2 in the top and bottom
lim x→0 (x-4)
Let x=0
lim x→0 (0-4) = -4
Filling in the table
x -.1 -.01 -.001 .001 .01 .1
f(x) -4.1 -4.01 -4.001 -3.999 -3.99 -3.9
Answer:
factor the expression =2y^2 (7y+1) or simplify it=14y^3 + 2y^2
Step-by-step explanation: