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2 years ago

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Sally had 10 peaches left at are roadside fruit stand. she went to the Orchard and picked more peaches to stock up at the stand

there are now 73 peaches of the stand write an equation that could be used to find how many peaches she picked

1 answer:

Diano4ka-milaya [45]2 years ago

8 0

Answer:73-10

Step-by-step explanation:

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A study conducted at a certain high school shows that 72% of its graduates enroll at a college. Find the probability that among

mixas84 [53]

Answer:

$P(X \geq 1) =1-P(X$

And we can use the probability mass function and we got:

$P(X=0)=(4C0)(0.72)^0 (1-0.72)^{4-0}=0.00615$

And replacing we got:

$P(X \geq 1) = 1-0.00615 = 0.99385$

Step-by-step explanation:

Let X the random variable of interest "number of graduates who enroll in college", on this case we now that:

$X \sim Binom(n=4, p=0.72)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We want to find the following probability:

$P(X \geq 1)$

And we can use the complement rule and we got:

$P(X \geq 1) =1-P(X$

And we can use the probability mass function and we got:

$P(X=0)=(4C0)(0.72)^0 (1-0.72)^{4-0}=0.00615$

And replacing we got:

$P(X \geq 1) = 1-0.00615 = 0.99385$

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3 years ago

Steve earned $7.40 per hour working his paper route. The first week, he worked 16 hours. After getting paid, he put $105 in the

prisoha [69]

Answer:17

Step-by-step explanation: Multiply Steve’s hourly wage ($7.40) by the hours he worked in a week (16 Hours) that would give you your weekly earnings which would be (7.40x16=$118.40) Then subtract what he saved in the bank from your total (118.40-105=$13.40) then you would divide $13.40 (his leftover money) by $0.75 to find the total number of carnival rides he could ride (13.40/0.75=17.86 rides and because he cannot ride 17 and 86 hundredths of a ride he would be able to ride 17 carnival rides.

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2 years ago

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Fire disturbance of terrestrial biomes is one of the primary factors in non-native plant species growth. A 2014 study by Pec and

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Answer:

Step-by-step explanation:

answer is attached below

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2 years ago

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Find the percent cost of the total spent on each equipment $36, fees $158, transportation $59

Evgen [1.6K]

Percent cost of the total spent on

each equipment = 14.23%,fees=62.45% and transportation = 23.32%.

As given in the question,

Money spent on

Each equipment = $36

Fees = $158

Transportation = $59

Total money spent = $( 36 + 158 + 59)

= $253

Percent cost of the total spent on

Each equipment = (36/253) × 100

= 14.23%

Fees = (36/253) × 100

= 62.45%

Transportation =(36/253) × 100

= 23.32%

Therefore, percent cost of the total spent on

each equipment = 14.23%,fees=62.45% and transportation = 23.32%.

Learn more about percent here

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1 year ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

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2 years ago