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Paladinen [302]
3 years ago
13

Algebra two graph problem!

Mathematics
1 answer:
Paladinen [302]3 years ago
5 0
It has no real solutions. To be precise, no real zeros (or roots).

The zeros (here called "solutions", I guess) are the points where the function intersects the x-axis: at those points the value of the function is zero. So they are solutions to the equation f(x)=0.

This function does not intersect the x-axis. Hence, no solutions.
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Let's see

Area of sector

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\\ \rm\Rrightarrow \dfrac{150}{360}\pi (4)²

\\ \rm\Rrightarrow \dfrac{5}{12}\pi (16)

\\ \rm\Rrightarrow \dfrac{5}{3}\pi(4)

\\ \rm\Rrightarrow \dfrac{20\pi}{3}

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7 0
2 years ago
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Akimi4 [234]

Answer:

see below

Step-by-step explanation:

(a)

( 2x - 5 )(3x^{2}  + 5x - 7)\\\\=2x(3x^2+5x-7)-5(3x^2+5x-7)\\\\=6x^3+10x^2-14x-15x^2-25x+35\\\\=6x^3+(10x^2-15x^2)+(-14x-25x)+35\\\\=6x^3-5x^2-39x+35

(b)

(2x-5)(3x^2+5x-7)=(5x-2)(3x^2+5x-7)\\\\\frac{1}{(3x^2+5x-7)}(2x-5)(3x^2+5x-7)= \frac{1}{(3x^2+5x-7)}(5x-2)(3x^2+5x-7)\\\\2x-5=5x-2\\\\2x-5x=-2+5\\\\-3x=3\\\\x=-1

only happens when x=-1, not always

3 0
3 years ago
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krek1111 [17]
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8 0
3 years ago
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Sergeu [11.5K]

Answer:

try socratic

Step-by-step explanation:

u need a phone for it to take the pics. are u can copy it and paste it to socratic on the computer. its an app

8 0
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