Answer:
20 N
Step-by-step explanation:
Since, both the forces are acting in opposite directions.
Therefore,

Evaluate 4 − 0 . 2 5 g + 0 . 5 h 4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g = 1 0 g=10g, equals, 10 and
abruzzese [7]
Not sure about the weird echo in the question but I think we're being ask to evaluate
4 - 0.25g + 0.5h
when g=10, h=5
That's
4 - 0.25(10) + 0.5(5) = 4 - 2.5 + 2.5 = 4
Answer: 4
the final speed in m/s of the 10.0 kg is 2.53 m/s .
<u>Step-by-step explanation:</u>
Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:
We know that in an elastic collision :
⇒ Total kinetic energy before collision = Total kinetic energy after collision
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the final speed in m/s of the 10.0 kg is 2.53 m/s .
It should be 40 ~
6*10=60
5*4=20
60-20=40