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aleksandr82 [10.1K]
4 years ago
7

Write a quadratic function in vertex form whose graph has the vertex (1, 0) and passes through the point (2, −17) .

Mathematics
1 answer:
lara [203]4 years ago
5 0

Answer:

Step-by-step explanation:

Given,

Vertex (h, k ) = (1,0)

Now,

We know,

f(x) = a(x-h)²+k

Since, it passess through (2, −17)

Put x = 2 and  y = - 17

or, -17 = a(2 - 1)² + 0

or, -17 = a

Now,

f(x) = a(x - h)² + k

     = -17(x - 1)² + 0

     = -17x² + 34x - 17

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These problems are solved using the trigonometric function. Trigonometric functions provides the ratio of different sides of a right-angle triangle.

<h3>What are Trigonometric functions?</h3>

The trigonometric function refer to function that are periodic in nature and which lend insight to the relationship between angles and the sides of a triangle that is right angled.

The solutions to x in the respective problems is given as follows:

1st.) x = 5 /Sin(30°)

x = 10

!) sin(45°) = 4/x

x = 4/sin(45°)

x = 4√2

I) Cos(45°) = √3 / x

x = √3 / Cos(45°)

x = √6

E) Tan(60°)

= (3√3) / x

x = (3√3) / 3

W) It is to be noted that for right-triangle that is isosceles in nature, the angle made by the legs and the hypotenuse is always 45°.

x = 45°

N) x² + x² = (7√2)²

x = 7

V) Tan(60°) = 7 / x

x = 7√3/3

K) x² + x² = (9)²

x = 9/√2

Y) Sin(60°) = 7√3/x

x = 14

M) Sin(30°) = x/11

x = 11/2

T) Sin(45°) = x/√10

x = √5

A) x + 2x + 90° = 180°

x = 30°

O) Sin(45°) = √2 / x

x = 2

R) Tan(30°) = x / 4

x = 4/√3

= 4√3 / 3

S) Sin(60°) = x / (10/3)

x = (5√3) / 3

Learn more about Trigonometric functions at:
brainly.com/question/1143565
#SPJ1

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