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aleksandr82 [10.1K]
3 years ago
7

Write a quadratic function in vertex form whose graph has the vertex (1, 0) and passes through the point (2, −17) .

Mathematics
1 answer:
lara [203]3 years ago
5 0

Answer:

Step-by-step explanation:

Given,

Vertex (h, k ) = (1,0)

Now,

We know,

f(x) = a(x-h)²+k

Since, it passess through (2, −17)

Put x = 2 and  y = - 17

or, -17 = a(2 - 1)² + 0

or, -17 = a

Now,

f(x) = a(x - h)² + k

     = -17(x - 1)² + 0

     = -17x² + 34x - 17

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Rashid [163]

Answer:

I'm assuming we're solving for the hypotenuse, which is 21.5

Step-by-step explanation:

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the square root of 461 is 21.47, or 21.5 rounded to the nearest tenth

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Answer:

Each person paid $24.

Step-by-step explanation:

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2 years ago
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Answer:

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