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never [62]
3 years ago
11

PLEASEEE HELLPPPPPPPPPPPPPPPP

Physics
1 answer:
cupoosta [38]3 years ago
3 0

Answer:

F = 2553.6 N

Explanation:

v² = u² + 2as

0² = 16² + 2a4.0

a = -32 m/s²

F = ma = 79.8(32) = 2553.6 N

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A technician wearing a brass bracelet enclosing area 0.00500 m2 places her hand in a solenoid whose magnetic field is 3.10 T dir
aliya0001 [1]

Explanation:

Given that,

Area enclosed by a brass bracelet, A=0.005\ m^2

Initial magnetic field, B_i=3.1\ T

The electrical resistance around the circumference of the bracelet is, R = 0.02 ohms

Final magnetic field, B_f=0.93\ T

Time, t=16\ ms=16\times 10^{-3}\ s

The expression for the induced emf is given by :

\epsilon=-\dfrac{d\phi}{dt}

\phi = magnetic flux

\epsilon=-\dfrac{d(BA)}{dt}

\epsilon=-A\dfrac{d(B)}{dt}

\epsilon=-A\dfrac{B_f-B_i}{t}

\epsilon=-0.005 \times \dfrac{0.93-3.1}{16\times 10^{-3}}

\epsilon=0.678\ volts

So, the induced emf in the bracelet is 0.678 volts.

Using ohm's law to find the induced current as :

V = IR

I=\dfrac{V}{R}

I=\dfrac{0.678}{0.02}

I = 33.9 A

or

I = 34 A

So, the induced current in the bracelet is 34 A. Hence, this is the required solution.

5 0
3 years ago
What can change shape and volume? PLz help :)
Rasek [7]
Gas has no certain shape However, its Volume can change with Differences in Heat and Pressure.
6 0
3 years ago
Read 2 more answers
Speed is
Agata [3.3K]

Yes, three good answers:

-- <span>a measure of how fast something is moving,
-- always measured in terms of a unit of distance divided by a unit of time,
and
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7 0
4 years ago
A car of 10 kg is moving at a speed of 5 m/s collides with a
Dmitriy789 [7]

Explanation:

M1U1+m2u2 = (m1+m2)vf

m1= 10kg

u1=5

m2=25

u2=0

vf=?

10×5+25×0=35 vf

50+0=35Vf

Vf=1.4m/s

7 0
3 years ago
A horizontal disk with a radius of 10 cm rotates about a vertical axis through its center. The disk starts from rest at t = 0 an
Tom [10]

Answer:

0.69s

Explanation:

10 cm = 0.1 m

Let t be the time that radial and tangential components of the linear acceleration of a point on the rim be equal in magnitude. At that time we have the angular velocity would be

\omega = \alpha t = 2.1 t

And so the radial acceleration is

a_r = \omega^2 r = (2.1t)^2 r = 2.1^2 t^2 * 0.1= 0.441 t^2 m/s^2

The tangential acceleration is always the same since angular acceleration is constant:

a_t = \alpha * r = 2.1 * 0.1 = 0.21 m/s^2

For these 2 quantities to be the same

a_r = a_t

0.441 t^2 = 0.21

t^2 = 0.21/0.441 = 0.4762

t = \sqrt{0.4762} = 0.69 s

6 0
4 years ago
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