All categories

3 years ago

How can icalculate 3 seconds and 5 meters into a speed?

1 answer:

8 0

To find speed you have to divide distance by time. In this case:

5 meters➗3 seconds = about 1.66666666 and so on m/s.

You could round to 1.67 or 1.7 if you'd like.

You might be interested in

Worth 25 points on my exam

I am Lyosha [343]

Initial velocity=20m/s
Final velocity=0m/s(As the car stops)
Acceleration=-8m/s^2
Distance=s=26m

We need to verify the thrid equation of kinematics here

$\\ \tt\longmapsto v^2-u^2=2as$

$\\ \tt\longmapsto 20^2=2(-8)s$

$\\ \tt\longmapsto 400=-16s$

$\\ \tt\longmapsto s=|400/-16|$

$\\ \tt\longmapsto s=25m$

The squirrel has a good luck ,Car gets stopped just 1m away from the squirrel .

7 0

2 years ago

Read 2 more answers

Which statement is TRUE?

Georgia [21]

The answer is B I know this because I’m Asian

4 0

2 years ago

Calculate the area of a square with a length of 5cm

mihalych1998 [28]

Answer:

25cm^2

Explanation:

area of square = side × side

length of side given = 5

area of this square = 5× 5

= 25cm^2

hope it helps

6 0

3 years ago

Read 2 more answers

A car is going south on I-69 at 33 m/s (74 mph). The car has good brakes so its maximum braking acceleration is – 8.5 m/s^2 . Tr

dmitriy555 [2]

Answer:

1.69515 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-33^2}{2\times -8.5}\\\Rightarrow s=64.06\ m$

The distance between the traffic and the car after braking is 120-64.06 = 55.94 m

Time = Distance / Speed

$\text{Time}=\frac{55.94}{33}\\\Rightarrow \text{Time}=1.69515\ seconds$

The reaction time cannot be more than 1.69515 seconds

4 0

3 years ago

Does a compressed spring transfer elastic energy to its surroundings?

shusha [124]

Answer:

Yes

Explanation:

5 0

3 years ago