Answer:
3, in both a), b)
Step-by-step explanation:
a) The slope of the line tangent to the curve that passes through the point (2,-10) is equal to the derivative of p at x=2.
Using differentiation rules (power rule and sum rule), the derivative of p(x) for any x is . In particular, the value we are looking for is .
If you would like to compute the equation of the tangent line, we can use the point-slope equation to get
b) The instantaneus rate of change is also equal to the derivative of P at the point x=2, that is, P'(2). This is equal to .
2x+3y, where x= the cost of one bag of apples and y= the cost of one bag of oranges.
Answer:
≈$4607
Step-by-step explanation:
I will assume it's compounded yearly.
Apply the compound interest formula.
A = Total
P = Initial Principle
r = Interest Rate
n = number of interest in every t period
t = number of periods
In the case,
P = 3500
r = 3.1% = 0.031
n = 1
t = 9
Hence,
A ≈ 4607 (nearest whole number)
Answer:
The equation to represent the account balance in t years
Step-by-step explanation:
Given the compound interest equation
here
A represents Accrued Amount (principal + interest)
P represents Principal Amount
I represent Interest Amount
r represents the Annual interest rate
t represents Time Involved in years
n represents the number of compounding periods per unit t
As we are given that the interest is compounded semi-annually
i.e. n = 2
so substituting n = 2 in the equation
∵ n = 2
Thus, the equation to represent the account balance in t years
Answer:
A=24, B=40, P=60
Step-by-step explanation:
<em>given: </em>
<em>P+A+B=124</em>
<em>2P+B=160</em>
<em>P+2A+2B=188</em>
___________
P=188-2A-2B
P=124-A-B
188-2A-2B=124-A-B
188-A-B=124
188=124+A+B
A+B=64
___
P+A+B=124
P=60
___
2P+B=160
120+B=160
B=40
___
A+B=64
A=24
___
If we substitute each variable in the three given equations for these values, the equations hold true. Therefore, these are the correct values.