Draw the following triangle after a translation 2 units to the left and 1 unit down.

A square pyramid is shown sitting on its base.

sesenic [268]

Answer:

312

Step-by-step explanation:

First we find the measure of the basea and that is 144 becuase 12x12

To find one side we do b*h over 2 and that is 7x12/2 which is 42 then we know that there are 4 more of those sides and we get 42*4 168

When we add 144+168 we will get 312

5 0

3 years ago

Please help, will mark brainliest, do not do for points or I will report, explanation please or no brainliest

sladkih [1.3K]

Answer:

to multiply-----

(2y-1)(2y+1)

2y(2y+1)-1(2y+1)

4y^2+2y-2y-1

=4y^2-1

4 0

3 years ago

Read 2 more answers

if 5 team of men each can build a house in 15 days how many houses can be build in 30 days if you have 6 team of 5 men

iren [92.7K]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

5TH GRADE LEVEL QUESTION: Look at photo and list it step by step GIVING OUT BRAINLIEST.

jasenka [17]

Answer:

(3+4x4)-7

(3+16)-7

19-7

12

4 0

3 years ago

Complete the table of values

Agata [3.3K]

Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, $3^{-2} =
\frac{1}{3^{2} }$ .
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, $(\frac{3}{4}) ^{3} = \frac{ 3^{3} }{4^{3} }$ .
3) The zero exponent rule says that any number raised to zero is 1. For example, $3^{0} = 1$ .


Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is $y = 4^{-x}$ . The x-values are:
1) x = 0
Plug this into $y = 4^{-x}$ to find letter a:
$y = 4^{-x}\\
y = 4^{-0}\\
y = 4^{0}\\
y = 1$

2) x = 2
Plug this into $y = 4^{-x}$ to find letter b:
$y = 4^{-x}\\ 
y = 4^{-2}\\ 
y = \frac{1}{4^{2}} \\ 
y= \frac{1}{16}$

3) x = 4
Plug this into $y = 4^{-x}$ to find letter c:
$y = 4^{-x}\\ 
y = 4^{-4}\\ 
y = \frac{1}{4^{4}} \\ 
y= \frac{1}{256}$


Problem 2
The x-values are in the left column. The title of the right column tells you that the function is $y = (\frac{2}{3})^x$ . The x-values are:
1) x = 0
Plug this into $y = (\frac{2}{3})^x$ to find letter d:
$y = (\frac{2}{3})^x\\
y = (\frac{2}{3})^0\\
y = 1$

2) x = 2
Plug this into $y = (\frac{2}{3})^x$ to find letter e:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\
y = \frac{4}{9}$

3) x = 4
Plug this into $y = (\frac{2}{3})^x$ to find letter f:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}$

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Answers:
a = 1
b = $\frac{1}{16}$ 
c = $\frac{1}{256}$
d = 1
e = $\frac{4}{9}$
f = $\frac{16}{81}$

5 0

3 years ago