All categories

3 years ago

If 100 cm id 1 m than how many cm are there are 13m

Mathematics

2 answers:

MrRissso [65]3 years ago

5 0

100 times 13 which is 1300, so in 13 m there is 1300 cm

postnew [5]3 years ago

3 0

The question requires you skills in doing multiplication or division. Ratio and proportion would also do here.
The topic here is about conversion.
You are given that 100 cm = 1m
Then how about 13 m?

100 cm : 1 m = X : 13m
100 cm * 13m = 1m * x
1300 = 1m * X
X = 1300 cm

So 13m is equal to 1,300 cm

You might be interested in

5. It is known that AABC = ADEF. If AB = 5, BC = 10, AC = 8, and DF = 2x-6, then solve for the value of

lorasvet [3.4K]

Answer:

The value of x is 7

Step-by-step explanation:

we know that

If two figures are congruent, then the corresponding angles and the corresponding sides are equal

In this problem

Triangles ABC and DEF are congruent

ABC≅DEF

therefore

AB=DE ----> equation A

AC=DF ----> equation B

BC=EF ----> equation C

Substitute the given values in the equation B

$8=2x-6$

Solve for x

$2x=8+6$

$2x=14$

$x=7$

therefore

The value of x is 7

The draw in the attached figure

3 0

3 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

Simplify the expression 4 + 3(x + 2)

kap26 [50]

Answer: 3x+10

You welcome!

5 0

2 years ago

Which segment is a diameter of this circle? Ο TX O VX Ο XY

professor190 [17]

Answer:

The answer is VX.

Step-by-step explanation:

This is because the line segment VX, reaches from one end of the circle to the other, touch both sides of the circle. The other options do not make sense since segment XY does not go through the center of the circle and TX is the radius of the circle. The radius is half the diameter of the circle.

Therefore, the answer is VX.

5 0

2 years ago

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$