Answer:
The value of x is 7
Step-by-step explanation:
we know that
If two figures are congruent, then the corresponding angles and the corresponding sides are equal
In this problem
Triangles ABC and DEF are congruent
ABC≅DEF
therefore
AB=DE ----> equation A
AC=DF ----> equation B
BC=EF ----> equation C
Substitute the given values in the equation B

Solve for x



therefore
The value of x is 7
The draw in the attached figure
Answer:
correct option is C) 2.8
Step-by-step explanation:
given data
string vibrates form = 8 loops
in water loop formed = 10 loops
solution
we consider mass of stone = m
string length = l
frequency of tuning = f
volume = v
density of stone =
case (1)
when 8 loop form with 2 adjacent node is
so here
..............1

and we know velocity is express as
velocity = frequency × wavelength .....................2
= f ×
here tension = mg
so
= f ×
..........................3
and
case (2)
when 8 loop form with 2 adjacent node is
..............4

when block is immersed
equilibrium eq will be
Tenion + force of buoyancy = mg
T + v ×
× g = mg
and
T = v ×
- v ×
× g
from equation 2
f ×
= f ×
.......................5
now we divide eq 5 by the eq 3

solve irt we get

so
relative density 
relative density = 2.78 ≈ 2.8
so correct option is C) 2.8
Answer:
The answer is VX.
Step-by-step explanation:
This is because the line segment VX, reaches from one end of the circle to the other, touch both sides of the circle. The other options do not make sense since segment XY does not go through the center of the circle and TX is the radius of the circle. The radius is half the diameter of the circle.
Therefore, the answer is VX.
The range of the equation is 
Explanation:
The given equation is 
We need to determine the range of the equation.
<u>Range:</u>
The range of the function is the set of all dependent y - values for which the function is well defined.
Let us simplify the equation.
Thus, we have;

This can be written as 
Now, we shall determine the range.
Let us interchange the variables x and y.
Thus, we have;

Solving for y, we get;

Applying the log rule, if f(x) = g(x) then
, then, we get;

Simplifying, we get;

Dividing both sides by
, we have;

Subtracting 7 from both sides of the equation, we have;

Dividing both sides by 2, we get;

Let us find the positive values for logs.
Thus, we have,;


The function domain is 
By combining the intervals, the range becomes 
Hence, the range of the equation is 