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3 years ago

14

Simplify the fraction: 2160/10

2 answers:

anzhelika [568]3 years ago

7 0

Answer:

1080/2 = 540/1

Step-by-step explanation:

2160/10

NARA [144]3 years ago

3 0

Answer:

1080/2 216/1

Step-by-step explanation:

Divide 1080/2 by 5, and 216/1 by 10, and this is what I got

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Need help - check image

alukav5142 [94]

Answer:

All real numbers

Step-by-step explanation:

The range is the possible output values

This is a line and the output goes from negative infinity to positive infinity

The range is all real numbers

7 0

4 years ago

Read 2 more answers

What is 60 divided by 95 (or is it the other way around?)

Rufina [12.5K]

Answer:

it would be 95 divided by 60

Step-by-step explanation:

but the answer to that is 1.5833333333333333333

4 0

3 years ago

Choose the two rectangular prisms that have a volume of 36 cm”.

Lina20 [59]

Answer:

B & D

Step-by-step explanation:

Volume is calculated as:

$Volume = Length * Width * Height$

For (a):

$Length = 3cm$

$Width = 4cm$

$Height = 5cm$

$Volume = 3cm * 4cm * 5cm$

$Volume = 60cm^3$

For (b):

$Length = 3cm$

$Width = 4cm$

$Height = 3cm$

$Volume = 3cm * 4cm * 3cm$

$Volume = 36cm^3$

For (c):

$Length = 4cm$

$Width = 2cm$

$Height = 2cm$

$Volume = 4cm * 2cm * 2cm$

$Volume = 16cm^3$

For (d):

$Length = 2cm$

$Width = 3cm$

$Height = 6cm$

$Volume = 2cm * 3cm * 6cm$

$Volume = 36cm^3$

<em>There's no need to check for (e)</em>

<em>Option b and d answers the question</em>

5 0

3 years ago

The vertices of a backyard are W(10,30),X(10,100),Y(110,100),Z(50,30). The coordinates are measured in feet. The line segment XZ

MariettaO [177]

Given vertices W(10,30), X(10,100), Y(110,100), Z(50,30) of a backyard, find distances WX, XY, YZ, ZW and XZ:

1. $WX=\sqrt{(10-10)^2+(30-100)^2}=\sqrt{70^2}=70\ ft;$

2. $XY=\sqrt{(110-10)^2+(100-100)^2}=\sqrt{100^2}=100\ ft;$

3. $YZ=\sqrt{(110-50)^2+(100-30)^2}=\sqrt{60^2+70^2}=10\sqrt{85}\ ft;$

4. $ZW=\sqrt{(50-10)^2+(30-30)^2}=\sqrt{40^2}=40\ ft;$

5. $XZ=\sqrt{(10-50)^2+(100-30)^2}=\sqrt{40^2+70^2}=10\sqrt{65}\ ft.$

Then:

1. the area

$A_{WXZ}=\sqrt{\frac{70+40+10\sqrt{65}}{2}\\\cdot (\frac{70+40+10\sqrt{65}}{2}-70)\cdot (\frac{70+40+10\sqrt{65}}{2}-40)\cdot (\frac{70+40+10\sqrt{65}}{2}-10\sqrt{65})}=\\ \\=1400\ ft^2.$

2. the area

$A_{XYZ}=\sqrt{\frac{100+10\sqrt{85}+10\sqrt{65}}{2}\cdot (\frac{100+10\sqrt{85}+10\sqrt{65}}{2}-100)}\cdot\\ \\\cdot\sqrt{(\frac{100+10\sqrt{85}+10\sqrt{65}}{2}-10\sqrt{85})\cdot (\frac{100+10\sqrt{85}+10\sqrt{65}}{2}-10\sqrt{65})}=3500\ ft^2.$

Then

$\dfrac{A_{XYZ}}{A_{WXZ}}=\dfrac{3500}{1400}=2.5$ times greater.

6 0

4 years ago

What is the equation for the line that passes through the point (-7,-7) and has a slope of 1?

sladkih [1.3K]

Answer:

Step-by-step explanation:

4 0

3 years ago