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Vladimir79 [104]
3 years ago
5

Oliver's Flavored Popcorn comes in cylindrical tins divided into three equal sections of caramel, cheese, and buttered flavors.

If the tin is 10 inches in diameter and 15 inches tall, what is the volume to the nearest tenth of only the cheese popcorn?
Mathematics
1 answer:
Luden [163]3 years ago
3 0

Answer:

The volume of only the cheese popcorn is 392.5 cubic inches.

Step-by-step explanation:

To determine the volume of only the cheese popcorn,

First, we will determine the volume of the cylindrical tin

The volume of a cylinder is given by

V = πr²h

Where V is the volume of the cylinder

π is a constant, (Take π = 3.14)

r is the radius of the cylinder

and h is the height of the cylinder

From the question, the tin is 10 inches in diameter and 15 inches tall.

Diameter = 10 inches, therefore, we can find radius

Radius = Diameter/2 = 10/2 = 5 inches

r = 5 inches

h = 15 inches

Now, putting the values into the equation, we get

V = 3.14 × 5² × 15

V = 1177.5 cubic inches

This is the volume of the cylindrical tin.

Since the cylindrical tin is divided into three equal sections of caramel, cheese, and buttered flavors, then the volume of only the cheese popcorn will be one-third of the total volume of the cylindrical tin.

∴ The volume of only the cheese popcorn = 1/3 × 1177.5 = 392.5 cubic inches

Hence, the volume of only the cheese popcorn is 392.5 cubic inches.

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Two-fifths of the square of a number j
fredd [130]

Answer:

\frac{2}{5}j^{2}

Step-by-step explanation:

Let

j ------> the number

we know that

The square of a number is equal to multiply the number by itself

so

The square of j is

j*j=j^{2}

so

Two-fifths of the square of a number j is the same that multiply the fraction 2/5 by the square of j

\frac{2}{5}j^{2}

7 0
3 years ago
Can someone help me Determine the intercepts of the line.
slavikrds [6]
Greetings!

To find the y-intercept, we can arrange the equation in slope y-intercept form:
y=mx+b

Rearrange:
y+1=3(x-4)

y+1=3x-12

y=3x-13

The y-intercept is: -13 
\boxed{(0,-13)}

To find the x-intercept, we can input the value <<0>> in the place of y, as every x-intercept only occurs when y=0:
(0)=3x-13

Solve for x:
0=3x-13

13=3x

\frac{13}{3}= \frac{3x}{3}

x=\frac{13}{3}

The x-intercept is: \frac{13}{3}
\boxed{(\frac{13}{3},0)}

I hope this helped!
-Benjamin






5 0
3 years ago
Day Drive 270 miles and 6 hours how many miles do you drive in 13 hours ​
NikAS [45]

Answer:

The answer is

<h2>585 miles</h2>

Step-by-step explanation:

In order to solve this question we use ratio and proportion

From the question

Day Drive 270 miles in 6 hours

So in order to find the distance drove in 13 hours, we compare the distance drove in 6 hours to the distance drove in 13 hours and solve

That's

if in 6 hours Day drove 270 miles

Then in 13 hours the person will drive

\frac{13  \times 270}{6}  =  \frac{3510}{6}

We have the final answer as

<h3>585 miles</h3>

Hope this helps you

7 0
3 years ago
My friend needed help with this and I found the height through the theorem but can't figure out how to get the base of the overa
Aleksandr-060686 [28]

You found CD from the Pythagorean theorem to be ...

... CD = √(5² -2²) = √21

Since triangle ADC ~ triangle ACB, the ratios of corresponding sides are the same:

... AC/AD = AB/AC

... AB = AC²/AD

... AB = 5²/2 = 12.5 . . . . . . . the base of the overall triangle

_____

Then the area (A) is ...

... A = (1/2)bh

... A = (1/2)(12.5)(√21) ≈ 28.64 square units

_____

As you see here, the altitude of a right triangle divides it into three similar triangles. From smallest to largest, they are ...

... ADC ~ CDB ~ ACB

You can figure this using AAA similarity, since the smallest and largest triangles listed above share an acute angle vertex (∠A). That, together with the right angle, means all angles are congruent. After that, then you know ∠ACD ≅ ∠CBD, so you can show the middle sized triangle is similar to the other two.

6 0
3 years ago
The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
grigory [225]

Answer:

142.2 meters.  

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

Let us find total surface area of box using surface area formula of cuboid.

\text{Total surface area of cuboid}=2(lb+bh+hl), where,

l = Length of cuboid,

b = Breadth of cuboid,

w = Width of cuboid.

\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

\text{Total surface area of box}=2(2520+432+840)

\text{Total surface area of box}=2(3792)

\text{Total surface area of box}=7584

Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0
3 years ago
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