Ask question

Ask question

All categories

Naddika [18.5K]

2 years ago

7

PLEASE HELP IF YOU CAN! IM DESPERATE! DUE TODAY!

2 answers:

kodGreya [7K]2 years ago

8 0

Answer:

Step-by-step explanation:

sukhopar [10]2 years ago

6 0

Answer:

2x+6=-8(x>=-7), 2x+3<9(x<3), 2x-4<=-8(x<=-2), -x-8>=-5(x<=-3), x+-4<=-3(x<=1)

Step-by-step explanation:

You might be interested in

What is the area of a semicircle with the diameter of 15

Alina [70]

Answer:

you divide 15 by 2 to get the radius, then do pie times radius to the second power, so

3.14*7.5*7.5= 23.55

that is ur answer!

Step-by-step explanation:

7 0

2 years ago

Henry's mom is in charge of buying lemonade for his soccer team this week she plans on every player receiving 7/8 of a cup of le

Katena32 [7]

If each player will receive 7/8 of a cup, and there are a total of 20 cups of lemonade, then the number of servings that can be made is equal to:

20 cups divided by (7/8 cup per player)
20 / (7/8) = 20 * (8/7) = 160/7 = 22 and 6/7 (round down since we're looking for complete servings)
This means that 22 complete servings can be made.

5 0

2 years ago

1 ½ x 4 2/9 = <br><br> 2 ⅘ x ⅕ = <br><br> 4 3/7 x ⅚ =<br><br> 6/6 x 1 ¼ = 1 ¼

irina [24]

For the first 6 1/3
second is 14/25
third 2 29/42

7 0

2 years ago

Svetradugi [14.3K]

Answer:

The Range is the set of all outputs for a function
The Domain is the set of all inputs for a function

For example

f(x)=x+3

Here Domain and range both are set of all real numbers

6 0

2 years ago

Read 2 more answers

Two shooters, Rodney and Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark

Sedaia [141]

Complete Question

Answer:

a

$SE = 0.66}$

b

$-3.29 < \mu_1 - \mu_2 < -0.70$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The first sample mean is $\= x _1 = 8$

The second sample mean is $\= x _2 = 10$

The first variance is $v_1 = 0.25$

The first variance is $v_2 = 0.55$

Given that the confidence level is 95% then the level of significance is 5% = 0.05

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the first standard deviation is

$\sigma_1 = \sqrt{v_1}$

=> $\sigma_1 = \sqrt{0.25}$

=> $\sigma_1 = 0.5$

Generally the second standard deviation is

$\sigma_2 = \sqrt{v_2}$

=> $\sigma_2 = \sqrt{0.55}$

=> $\sigma_2 = 0.742$

Generally the first standard error is

$SE_1 = \frac{\sigma_1}{\sqrt{n} }$

$SE_1 = \frac{0.5}{\sqrt{60} }$

$SE_1 = 0.06$

Generally the second standard error is

$SE_2 = \frac{\sigma_2}{\sqrt{n} }$

$SE_2 = \frac{0.742}{\sqrt{60} }$

$SE_2 = 0.09$

Generally the standard error of the difference between their mean scores is mathematically represented as

$SE = \sqrt{SE_1^2 + SE_2^2 }$

=> $SE = \sqrt{0.06^2 +0.09^2 }$

=> $SE = 0.66}$

Generally 95% confidence interval is mathematically represented as

$(\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } * SE) < \mu_1 - \mu_2 < (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } * SE)$

=> $(8 -10) -(1.96 * 0.66) < \mu_1 - \mu_2 < (8-10) +(Z_{\frac{\alpha }{2} } * 0.66)$

=> $-3.29 < \mu_1 - \mu_2 < -0.70$

5 0

3 years ago