Where P = 5000, r = 10% = .10, n = 4 (since its compounded quarterly), and t = 20
Now we plug all variables into the equation.
The answer is $<span>36,047.84</span>
I'M IN A TIMED TEST... HELP PLZ!!!The volume of this sphere is StartFraction 500 pi Over 3 EndFraction cubic inches. What is its
2 answers:
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Where P = 5000, r = 10% = .10, n = 4 (since its compounded quarterly), and t = 20
Now we plug all variables into the equation.
The answer is $<span>36,047.84</span>
Answer:
The proof is given below.
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
Answer:
The net outward flux across the boundary of the tetrahedron is: -4
Step-by-step explanation:
Given vector field F = ( -2x, y, - 2 z )
= -2 + 1 -2
= -3
According to divergence theorem;
Flux =
x+y+z = 2; Octant
x from 0 to 2
y from 0 to 2 -x
z from 0 to 2-x-y
= -4
Thus; The net outward flux across the boundary of the tetrahedron is: -4