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zalisa [80]
3 years ago
15

Mona wants to buy carpet for a floor in her house.

Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0
What are the prices?
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The domain of the function f(x) = 3x3 is {2, 5}. What is the function’s range?
Sholpan [36]
The domain is {2,5} which the set containing the numbers 2 and 5. I'm assuming that the function is f(x) = 3x3<span>. So...

</span>when x = 2, f(x) = 3*23<span> = 3*8 = 24.
</span>when x = 5, f(x) = 3*53<span> = 3*125 = 375.

so this means the functions range is {24, 375}

hope this helped you out</span>
6 0
3 years ago
A parachutists rate during the freefall reaches 189 km/h. What is the rate in meters per second? At this rate how many meters wi
Lera25 [3.4K]
1 km = 1000m
1 hr = 3600 s

189 km/h
189 * 1000 / 3600 m/s
189*5/18 m/s
945/18 m/s
315/6 m/s
105/2 m/s
52.5 m/s

in 10 s
52.5*10
525 m
3 0
3 years ago
A pharmaceutical company sells bottles of 500 calcium tablets in two dosages: 250 milligram and 500 milligram. Last month, the c
Svetach [21]
X = 250 mg tabs
y = 500 mg tabs

2200x + 1800y = 39200....multiply by -1
2200x + 2200y = 44000
--------------------------------
-2200x - 1800y = - 39200 (result of multiplying by -1)
2200x + 2200y = 44000
--------------------------------add
400y = 4800
y = 4800/400
y = 12...... the 500 mg tabs (y) costs $ 12 per bottle

2200x + 2200y = 44000
2200x + 2200(12) = 44000
2200x + 26400 = 44000
2200x = 44000 - 26400
2200x = 17600
x = 17600/2200
x = 8 <== the 250 mg tabs (x) costs $ 8 per bottle
3 0
3 years ago
Read 2 more answers
What is 40t^2 - 400t + 500 = 0 factored
Dmitry_Shevchenko [17]
= 40(t^2 - 10t + 12.5)  answer
6 0
3 years ago
Bill's school is selling tickets to a spring musical. On the first day of ticket sales the school sold 5 adult tickets and 14 st
wariber [46]

Answer: The price of an adult ticket = $6

The price of a student ticket = $12

Step-by-step explanation:

Let the price of an adult ticket be a

Let the price of a student ticket be b.

From the question,

5a + 14b = 198 ...... equation i

10a + 8b = 156....... equation ii

Multiply equation i by 10

Multiply equation ii by 5

50a + 140b = 1980 ...... equation iii

50a + 40b = 780 ....... equation iv

Subtract iv from iii

100b = 1200

b = 1200/100

b = 12

Put the value of b into equation ii

10a + 8b = 156

10a + 8(12) = 156

10a + 96 = 156

10a = 156-96

10a = 60

a = 6

The price of an adult ticket = $6

The price of a student ticket = $12

8 0
3 years ago
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