Answer:
We are 98% confident interval for the mean caffeine content for cups dispensed by the machine between 107.66 and 112.34 mg .
Step-by-step explanation:
Given -
The sample size is large then we can use central limit theorem
n = 50 ,
Standard deviation
= 7.1
Mean
= 110
1 - confidence interval = 1 - .98 = .02
= 2.33
98% confidence interval for the mean caffeine content for cups dispensed by the machine = 
= 
= 
First we take + sign
= 112.34
now we take - sign
= 107.66
We are 98% confident interval for the mean caffeine content for cups dispensed by the machine between 107.66 and 112.34 .
Answer: 8
Step-by-step explanation:
As corresponding sides of similar triangles are proportional,

<span>I think you meant this: (3m/m-6)*(5m^3-30m^2/5m^2)
If that's the case, the simplified form:
=3m</span>
24q-8=11 (use distributive property)
24q= 11+8
24q = 20
q= 20/24
q= 0.8
Answer:
JMK
Step-by-step explanation: