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Igoryamba
3 years ago
14

Bill's school is selling tickets to a spring musical. On the first day of ticket sales the school sold 5 adult tickets and 14 st

udent tickets for a total of $198. The school took in $156 on the second day by selling 10 adult tickets and 8 student tickets. Find the price of an adult ticket and the price of a student ticket.
Mathematics
1 answer:
wariber [46]3 years ago
8 0

Answer: The price of an adult ticket = $6

The price of a student ticket = $12

Step-by-step explanation:

Let the price of an adult ticket be a

Let the price of a student ticket be b.

From the question,

5a + 14b = 198 ...... equation i

10a + 8b = 156....... equation ii

Multiply equation i by 10

Multiply equation ii by 5

50a + 140b = 1980 ...... equation iii

50a + 40b = 780 ....... equation iv

Subtract iv from iii

100b = 1200

b = 1200/100

b = 12

Put the value of b into equation ii

10a + 8b = 156

10a + 8(12) = 156

10a + 96 = 156

10a = 156-96

10a = 60

a = 6

The price of an adult ticket = $6

The price of a student ticket = $12

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HELPPP!!!!!!
Furkat [3]
<h3>Answer: Choice D)  31.2 miles</h3>

This value is approximate.

============================================================

Explanation:

Let's focus on the 48 degree angle. This angle combines with angle ABC to form a 90 degree angle. This means angle ABC is 90-48 = 42 degrees. Or in short we can say angle B = 42 when focusing on triangle ABC.

Now let's move to the 17 degree angle. Add on the 90 degree angle and we can see that angle CAB, aka angle A, is 17+90 = 107 degrees.

Based on those two interior angles, angle C must be...

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To sum things up so far, we have these known properties of triangle ABC

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Let's use the law of sines to find side b, which is opposite angle B. This will find the length of side AC (which is the distance from the storm to station A).

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Make sure your calculator is in degree mode.

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