The closure temperature represents the point when isotopes are no longer free to move out of a crystal lattice.
Answer: Option C
<u>Explanation:</u>
The closure temperature can also be termed as blocking temperature. It is mostly used in radiometric dating. As the temperature decreases, below a certain point the isotopes may get freeze in their lattice positions. And there may be slowing of diffusion.
At the closure temperature, that rate of diffusion will be zero as the isotopes will be no longer free to move out of crystal lattice. So, this is termed as closure or blocking temperature. As the isotopes loose their ability to move, their concentration will remain fixed in their position leading to measurement of radiation dating.
<h2>Answer: Transpiration
</h2>
Vegetal transpiration is the loss of water in the form of vapor, in the plant through its different parts, especially its leaves.
In this process, soil water is absorbed by the roots of the plant and transported in liquid form to the leaves to be converted into water vapor, while a part is used in photosynthesis. That is why vegetal transpiration is considered a vital function in the photosynthesis process.
This is possible because the leaves have small pores that allow water to escape into the atmosphere in the form of vapor and absorb carbon dioxide. Then, most of the water in the plants is used in the process of transpiration and only a small percentage is retained in liquid state and used for its growth and storage.
Stress = force / area
= 4.8 x 10³ / 1.2 x 10^-4
= 4 x 10⁷ N /m²
YOUNGS MODULAS = stress / strain
= 4 x 10⁷ / 1.2 x 10^11
= 3.3 x 10^-4
INCREMENT OF LENGTH = longitudinal length x intitial length
= ( 3.3 x 10^-4 ) x 4
= 13.2 x 10^-4 m
= 13.2 mm
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Answer:
D) 720 kmph
Explanation:
First, let's find what distance this aeroplane covered. Distance (d) is the product of speed and time - here, we have a speed of 240 kmph and a time of 5 hours, gives us
km
Using that same fact, we can set up a new equation to solve for speed (s) when we have a distance of 1200 km and a time of 1 2/3 hours. For the sake of cleanliness, I'm gonna rewrite 1 2/3 as the improper fraction 5/3:
Multiplying both sides of the equation by 3/5:
kmph
So our answer is D.
