Answer:
8) 1500 feet
9) 20 miles
10) 4 Days
11) 2250 miles
12) 1 hour and 5 minutes
13) 27.27miles per hour
Explanation
8) There are 60 seconds in one minute so 60x25=1500 feet
9) 30 minutes is half of an hour so 40 miles ÷ 2 = 20 miles
10) 12x4=48
11) 500 miles x 4.5 hours is 2250 miles
12) Train leaves at 3pm after 60 miles it will be 4 pm and after 5 more miles 4:05 pm so 1 hour and 5 minutes
13)
Elmo = 40 minutes and 5 miles
Bert and Ernie = 45 minutes and 15 miles
Cookie Monster = 20 minutes and 10 miles
Home = 5 minutes abd 20 miles
Average Speed including stops is 27.27 miles per hour
The spiral structure of the milky way can be explained by long lived quasi-static density waves<em>, </em><em>according to the lin-shu hypothesis. </em>Curiously, the waves of higher density gas and stars (seen as spiral arms) appear to remain static as stars move around the galaxy. This explained by assuming that the gravitational disturbances cause by the 'clumping' material in the arms does not affect the gravitational field of the galaxy as whole and is therefore negligible.
source: Astrophysicist
D. 980, this is the best answer because 35 x 7 is 980 :)
Answer:
Not possible
Explanation:
= longitudinal modulus of elasticity = 35 Gpa
= transverse modulus of elasticity = 5.17 Gpa
= Epoxy modulus of elasticity = 3.4 Gpa
= Volume fraction of fibre (longitudinal)
= Volume fraction of fibre (transvers)
= Modulus of elasticity of aramid fibers = 131 Gpa
Longitudinal modulus of elasticity is given by

Transverse modulus of elasticity is given by


Hence, it is not possible to produce a continuous and oriented aramid fiber.