All categories

3 years ago

After a nucleus with 85 protons undergoes alpha decay, it has ? protons.

Physics

1 answer:

Valentin [98]3 years ago

5 0

Answer:

After a nucleus with 85 protons undergoes alpha decay, it has 83 protons.

Explanation:

In an alpha particle there are two protons

In the given substance's nucleus, there are total of 85 protons

After the decay, the proton number reduce

The current proton number after decay is

85 -2 = 83

After a nucleus with 85 protons undergoes alpha decay, it has 83 protons.

You might be interested in

a car travels 10 miles east in 30 minutes. what is its velocity in miles per hour. what is its velocity in miles per hour?

nika2105 [10]

Answer:

popu

Explanation:

2u2uwju2i2je82jei

8 0

3 years ago

What circumstance would allow an officer to search a home even if they didn’t have a warrant?

Ipatiy [6.2K]

Answer:

Explanation:

The officer would have had permission regardless of anything else, kind of like letting someone into your house.

5 0

3 years ago

Spinning satellites are particularly stable. suppose that the astronauts launching a particular satellite decide to increase its

Crank

Supposing velocity is speed and direction, and momentum is mass*velocity, if the velocity increases by a factor of 5, then so should the momentum regardless of the whole space thing.

3 0

3 years ago

Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.400mm wide. The diffraction pattern is observed

kogti [31]

Answer:

a) $y_{first}=5.3mm$

b) $y_{second}=10.6-5.3 =5.3 mm$

Explanation:

The width of the central bright in this diffraction pattern is given by:

$y=\frac{m\lambda D}{a}$ when m is a natural number.

here:

m is 1 (to find the central bright fringe)
D is the distance from the slit to the screen
a is the slit wide
λ is the wavelength

So we have:

$y_{first}=\frac{633*10^{9}*3.35}{0.0004}$

$y_{first}=5.3mm$

Now, if we do m=2 we can find the distance to the second minima.

$y_{2}=\frac{2*633*10^{9}*3.35}{0.0004}$

$y_{2}=10.6 mm$

Now we need to subtract these distance, to get the width of the first bright fringe :

$y_{second}=10.6-5.3 =5.3 mm$

I hope it heps you!

4 0

3 years ago

please help In a video game, a ball moving at 0.6 meter/second collides with a wall. After the collision, the velocity of the ba

viva [34]

Answer:

the acceleration during the collision is: - 5 $\frac{m}{s^2}$

Explanation:

Using the formula:

$a=\frac{\Delta\,v}{\Delta\,t}$

we get:

$a=\frac{-0.4-0.6}{0.2} \,\frac{m}{s^2} =\frac{-1}{0.2} \,\frac{m}{s^2} =-5\,\,\frac{m}{s^2}$

4 0

3 years ago