The diagram below is divided into equal parts. Which shows the ratio of unshaded section to shaded sections

Ed deposited $6000 into a savings account 4 years ago. The simple interest rate is 3%. How much does Ed have in his account now?

Serga [27]

Answer:

$200,000

Step-by-step explanation:

6,000×100=600,000

600,000÷3=200,000

So $200,000

8 0

3 years ago

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Cecilia made the scale drawing of her bedroom using the scale 1 cm to 4 feet what statement describes another scale drawing that

Rufina [12.5K]

Answer:

B and D.

Step-by-step explanation:

Explanation:

a scale drawing that has a scale of 1 centimeter to 2 feet, with a width of 6 centimeters and a length of 8 centimeters

a scale drawing that has a scale of 1 centimeter to 8 feet with a width of 1.5 centimeters and a length of 2 centimeters

7 0

3 years ago

Please help urgently i am not sure what to do

Flura [38]

Step-by-step explanation:

5 * 5²

= 5 ^ (1 + 2)

= 5³

Hope it will help

7 0

3 years ago

Use complete sentences to describe why √-1 ≠ -√1

tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

Definition

$\displaystyle \large{ {y}^{2} = x} \\ \displaystyle \large{ y = \pm \sqrt{x} }$

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

Definition II

$\displaystyle \large{ {a}^{2} = a \times a = |b| }$

Where b is the result from a×a. Let's see an example.

Examples

$\displaystyle \large{ {2}^{2} = 2 \times 2 = 4} \\ \displaystyle \large{ {( - 2)}^{2} = ( - 2) \times ( - 2) = | - 4| = 4}$

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

$\displaystyle \large{ {y}^{2} = - 1}$

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

$\displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{ - 1} }$

Then where does plus-minus come from? It comes from one of Absolute Value propety.

Absolute Value Property I

$\displaystyle \large{ \sqrt{ {x}^{2} } = |x| }$

Solving absolute value always gives the plus-minus. Therefore...

$\displaystyle \large{ y = \pm \sqrt{ - 1} }$

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

$\displaystyle \large{ {y}^{2} = 1} \\ \displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{1} } \\ \displaystyle \large{ y = \pm \sqrt{1} }$

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

Conclusion

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0

2 years ago

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The manager of a warehouse would like to know how many errors are made when a product’s serial number is read by a bar-code read

stira [4]

The mean of the answer is 20.5 because you add all of the number together and divide by 6 because there's 6 numbers.
I'm sorry, but I don't know how to do the standard deviation...
Hope this helped!

4 0

3 years ago