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tester [92]
2 years ago
12

Helpppppppppz it’s to harddd

Mathematics
2 answers:
noname [10]2 years ago
5 0

Answer:

Step-by-step explanation:

Oh jeez

kari74 [83]2 years ago
5 0

Answer:

Try C hope this is right

Step-by-step explanation:

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PLSS HELPPP WITH MATH
ANTONII [103]

Answer: B sorry if im wrong

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A. {0,1,2,3,4}<br> B. {1,2,3,4}<br> C. {-1,0,1,2,3}<br> D. {-2,-1,0,1,2,3,4}
Harlamova29_29 [7]

Option D:

The set is {-2, -1, 0, 1, 2, 3, 4}.

Solution:

Given set:

\{x \in Z:-2 \leq x \leq 4\}

Z means integer values.

Integer means set of positive and negative values including zero.

-2 \leq x \leq 4

This means x lies between -2 and 4.

  • If x strictly less than -2 and greater than 4 means you don't have to include -2 and 4.
  • But here x less than or equal to -2 and greater than or equal to 4, so you have to include -2 and 4.

The integers are -2, -1, 0, 1, 2, 3 and 4.

So, x belongs to the set {-2, -1, 0, 1, 2, 3, 4}

Hence the given set is defined by the set  {-2, -1, 0, 1, 2, 3, 4}.

Option D is the correct answer.

6 0
3 years ago
What is the rule input numbers are 17 18 _ 28_40
Lelu [443]
19 27 28 29 30 315 64 29 46 is the 
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4 0
3 years ago
Find f.<br><br> A) 7.4<br><br> B) 8.2<br><br> C) 10.5<br><br> D) 11.1
tatyana61 [14]
F=72

g=6

------------

\cos { \left( F \right)  } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }

Therefore:

\cos { \left( 72 \right)  } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right)  } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }

\\ \\ 12e\cdot \cos { \left( 72 \right)  } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right)  } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 }  } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right)  }  \right) +36 }

But what is e?

E=76

G=32

g=6

And:

\frac { e }{ \sin { \left( E \right)  }  } =\frac { g }{ \sin { \left( G \right)  }  }

Which means that:

\frac { e }{ \sin { \left( 76 \right)  }  } =\frac { 6 }{ \sin { \left( 32 \right)  }  } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  }

If you take this value into account, you will discover that f is...

f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  } \left( \frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  } -12\cos { \left( 72 \right)  }  \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)

So I would have to say that the answer is approximately (c).
6 0
3 years ago
Which of the undefined terms is used to define the term parallel lines
scoundrel [369]
<span>x.line is the correct answer</span>
6 0
3 years ago
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