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sleet_krkn [62]
4 years ago
14

..vertex: (4, -1) f(3) = -6

Mathematics
1 answer:
s344n2d4d5 [400]4 years ago
4 0

Answer:

\huge\boxed{f(x)=-5(x-4)^2-1=-5x^2+40x-81}

Step-by-step explanation:

The vertex form of an equation of a parabola:

f(x)=a(x-h)^2+k

(h;\ k) - vertex

We have

vertex (4;\ -1)\to h=4;\ k=-1

f(3)=-6

Therefore we have:

f(x)=a(x-4)^2+(-1)=a(x-4)^2-1

Substitute x=3 and f(3)=-6

a(3-4)^2-1=-6\qquad|\text{add 1 to both sides}\\\\a(-1)^2=-6+1\\\\a(1)=-5\\\\a=-5

Finally:

f(x)=-5(x-4)^2-1=-5(x^2-2(x)(4)+4^2)-1\\\\=-5(x^2-8x+16)-1=-5x^2+(-5)(-8x)+(-5)(16)-1\\\\=-5x^2+40x-80-1=-5x^2+40x-81

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Answer:

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Step-by-step explanation:

If sin x = -3/5, then we have the following info as a starting point:

opposite side = -3 (implying that the angle is in either QIII or QIV), and

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3 years ago
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