I think the correct answer would be C. hope this helped !
Put x=5 in above function. J(x)= 39x. J(5) = 39x5 = 195.
A hawk is sitting on the branch of a tree Question Image ft above the ground. It flies 28.3 ft higher in the air, drops down by 8.2 ft, and then a short time later flies down another Question Image ft onto the branch of another tree. Write an expression that represents the change in the bird’s height. Which of the two branches is higher above the ground?
Please help me asap!
Will mark as Brainliest for first correct answer.
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
-32
Step-by-step explanation:
10–{22–[(−9)+(−11)]}
Work inside out
10–{22–[(-20)]}
Subtracting a negative is adding
10–{22+20}
10 - 42
-32
