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stiks02 [169]
3 years ago
12

Den

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
5 0

Answer:

Perimeter of ABCD - Perimeter of PQRS = 4x + 2

Step-by-step explanation:

i. For rectangle ABCD;

length, l = 2x -3

width, w = 4x + 5

Perimeter of a rectangle = 2(l + w)

Perimeter of ABCD = 2((2x -3) + (4x + 5))

                                = 2(2x -3 + 4x + 5)

                                = 2(6x + 2)

Perimeter of ABCD = 12x + 4

ii. For rectangle PQRS;

length, l = x - 1

width, w = 3x + 2

Perimeter of a rectangle = 2(l + w)

Perimeter of PQRS = 2((x - 1) + (3x + 2))

                                = 2(x - 1 + 3x + 2)

                                = 2(4x + 1)

Perimeter of PQRS = 8x + 2

So that,

Perimeter of ABCD - Perimeter of PQRS = (12x + 4) - (8x + 2)

                                          = 12x + 4 - 8x - 2

                                          = 4x + 2

Perimeter of ABCD - Perimeter of PQRS = 4x + 2

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Answer:

\frac{5}{14}

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Data provided in the question:

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