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sladkih [1.3K]
2 years ago
13

Figure A ~ Figure B

Mathematics
1 answer:
Nuetrik [128]2 years ago
8 0
176 f because they are equal the symbol mext to the word figure A its telling you that they are equal so basically you will just divide by two
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The cost of a company picnic varies directly as the number of employees attending the picnic. If a company picnic costs $362.25
Nataliya [291]

Answer:  

 So basically just 362.25 x 83 = 30066.75

6 0
3 years ago
A number is chosen at random from 1 to 25. Find the probability of selecting an odd number or multiples of 5. *
Ymorist [56]

Answer:

Odd number: 13/25 (52%)

Multiples of 5: 5/25 (20%)

Step-by-step explanation:

There are 13 odd numbers between 1 and 25 so you have a 13/25 chance which is 52% (13/25 = 0.52). There are 5 multiples of 2 between 1 and 25 so you have a 5/25 chance which is 20% (5/25 = 0.2).

8 0
3 years ago
PLSSS HELLLPPPP
-Dominant- [34]

Answer:

provided an easy explanation to give answer below

Step-by-step explanation:

prime numbers are only divisible by 1 and themselves.

2 - 10 prime numbers are

2 3 5 and 7

full list up to 81

2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 and 79

7 0
2 years ago
Read 2 more answers
Solve for q using both equation 1 and 2 question in pic
galina1969 [7]

Answer:

p=1/8     q=3/4

Step-by-step explanation:

-2p+7q=5

-6p+35q=51/2

cancel out a variable

(-5)(-2p+7q=5)

-6p+35q=51/2

10p-35q=-25

-6p+35q=51/2  =

4p=1/2

4p/4=1/2  /4

p=1/8

substitute p=1/8 into one of the equation to find q

-2p+7q=5

-2(1/8)+7q=5

-1/4+7q=5

7q=5+1/4

7q=21/4

q= 21/4  /7

q=3/4

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2
PIT_PIT [208]

Option (b) is your correct answer.

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given Trigonometric expression is

\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }

So, on rationalizing the denominator, we get

\rm \:  =  \: \dfrac{sin\theta }{1 + cos\theta }  \times \dfrac{1 - cos\theta }{1 - cos\theta }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}}

So, using this, we get

\rm \:  =  \: \dfrac{sin\theta (1  -  cos\theta )}{1 -  {cos}^{2}\theta  }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {sin}^{2}x +  {cos}^{2}x = 1}}}

So, using this identity, we get

\rm \:  =  \: \dfrac{sin\theta (1 -  cos\theta )}{{sin}^{2}\theta  }

\rm \:  =  \: \dfrac{1 - cos\theta }{sin\theta }

<u>Hence, </u>

\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta }   =  \: \dfrac{1 - cos\theta }{sin\theta } }}} \\

3 0
2 years ago
Read 2 more answers
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