Look at the picture, please answer correctly and no links.
1 answer:
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Answer:
a) 0.4452
b) 0.0548
c) 0.0501
d) 0.9145
e) 6.08 minutes or greater
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 4.7 minutes
Standard Deviation, σ = 0.50 minutes.
We are given that the distribution of length of the calls is a bell shaped distribution that is a normal distribution.
Formula:
a) P(calls last between 4.7 and 5.5 minutes)
b) P(calls last more than 5.5 minutes)
Calculating the value from the standard normal table we have,
c) P( calls last between 5.5 and 6 minutes)
d) P( calls last between 4 and 6 minutes)
e) We have to find the value of x such that the probability is 0.03.
P(X > x)
Calculation the value from standard normal z table, we have,
P(z < 2.75) = 0.997
Hence, the call lengths must be 6.08 minutes or greater for them to lie in the highest 3%.