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3 years ago

This question please; I’ve done all the others but this one has stumped me :/

Mathematics

1 answer:

vesna_86 [32]3 years ago

5 0

2 way table
cola water milk total
boy 12 4 16 32
girl 14 9 5 28
Total 28 13 21 60

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The science class is taking a field trip. There are a 20 students and a unknown number of adults. The bus holds 35 people at mos

AveGali [126]

It would be 15 because the 35 people at most minus the 20 students equals 15 so that would be the greatest number of adults allowed to be there.

5 0

3 years ago

Read 2 more answers

Solve for x and y <br> 8x-2y=24

TiliK225 [7]

Answer: For y it's y=4x−12 and for x it's x=12+y/4

Step-by-step explanation:

SOLVING FOR X

8x-2y=24

2(4x−y)=24

4x−y=24/2

4x−y=12

4x=12+y

x=12+y/4

SOLVING FOR Y

8x-2y=24

2(4x−y)=24

4x−y=24/2

4x−y=12

−y=12−4x

y=−12+4x

y=4x−12

Hope this helps, have a BLESSED AND WONDERFUL DAY! As well as a great Black History Month and Valentine's day! :-)

- Cutiepatutie ☺❀❤

8 0

3 years ago

G es to prove that if a, b, and c are integers, where a ≠ 0 and c ≠ 0, such that ac | bc, then a |

Alex Ar [27]

$ac\mid bc$ means there exists an integer $n$ such that $ac=bcn$ . We can divide both sides by $c$ because $c\neq0$ . This implies $a=bn$ for some integer, which is identically $a\mid b$ .

3 0

3 years ago

Genevieve is 3 years older than twice her brother’s age. Genevieve is 21 years old. Write an equation to find her brother’s age.

Simora [160]

Answer:

her brother is 9

Step-by-step explanation:

21-3=18 18 divided by 2 = 9

7 0

2 years ago

Read 2 more answers

In a population of similar households, suppose the weekly supermarket expense for a typical household is normally distributed wi

Rina8888 [55]

Answer:

P(Y ≥ 15) = 0.763

Step-by-step explanation:

Given that:

Mean =135

standard deviation = 12

sample size n = 50

sample mean $\overline x$ = 140

Suppose X is the random variable that follows a normal distribution which represents the weekly supermarket expenses

Then,

$X \sim N ( \mu \sigma)$

The probability that X is greater than 140 is :

P(X>140) = 1 - P(X ≤ 140)

$P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{140-135}{12})$

$P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{5}{12})$

$P(X>140) = 1 - P( Z\leq0.42)$

From z tables,

$P(X>140) = 1 - 0.6628$

$P(X>140) = 0.3372$

Similarly, let consider Y to be the variable that follows a binomial distribution of the no of household whose expense is greater than $140

Then;

$Y \sim Binomial (np)$

$Y \sim Binomial (50,0.3372)$

∴

P(Y ≥ 15) = 1- P(Y< 15)

P(Y ≥ 15) = 1 - ( P(Y=0) + P(Y=1) + P(Y=2) + ... + P(Y=14) )

$P(Y \geq 15) = 1 - \begin {pmatrix} ^{50}_0 \end {pmatrix} (0.3372)^0 (1-0,3372)^{50} + \begin {pmatrix} ^{50}_1 \end {pmatrix} (0.3372)^1 (1-0,3372)^{49} + \begin {pmatrix} ^{50}_2 \end {pmatrix} (0.3372)^2 (1-0,3372)^{48} +... + \begin {pmatrix} ^{50}_{50{ \end {pmatrix} (0.3372)^{50} (1-0,3372)^{0}$

P(Y ≥ 15) = 0.763

7 0

3 years ago