This question please; I’ve done all the others but this one has stumped me :/

Mathematics

1 answer:

vesna_86 [32]3 years ago

5 0

2 way table
cola water milk total
boy 12 4 16 32
girl 14 9 5 28
Total 28 13 21 60

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8x = 7x + 3<br><br> Would I combine the 8x and the 7x at all in this equation?

Kryger [21]

Yes...thats what u want to do. you want to get the x terms on one side and everything else on the other side.

8x = 7x + 3....so we will subtract 7x from both sides
8x - 7x = 7x - 7x + 3....simplify
1x, or just x = 3 (because ur 7x's cancelled each other out)

so ur answer is : x = 3

and u can check ur answer by subbing it back into the original equation.
8x = 7x + 3
8(3) = 7(3) + 3
24 = 21 + 3
24 = 24 (correct)

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Sam is loading a freight elevator with boxes that are 55 pounds each. If the freight elevator can safely hold up to 3000 lbs, ho

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Therefore, Sam can put 54 boxes.

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An eastbound train left at 12pm. Four hours later, a westbound train left the same station. At 8pm, the two trains were 400 mile

Ainat [17]

Answer:

Step-by-step explanation:

Gotta love these motion problems!

d = rt is what we need here to solve this, along with some logic.

If the EB (eastbound) train left at noon then at the end of its travels, at 8pm to be specific, it was traveling for 8 hours. Therefore, for the EB train, t = 8.

If the WB train left at 4 pm then at the end of its travels, also at 8pm, it was traveling for 4 hours. Therefore, for the WB train, t = 4.

The distance between the trains is given as 400 miles. That 400 mile distance is due to the fact that each train traveled a distance of rate*time. The distance the WB train traveled + the distance the EB train traveled = 400 miles. Now we just need to find out the distance each traveled in its respective time frame.

For the EB train. We already know that t = 8. We do not know how fast it's going, so rate is just r. In the distance formula, d = rt:

$d_{EB}=8r$

For the WB train. We already know that t = 4. We do not know this rate either, but we do know that it is traveling 10 mph faster than the EB train, so rate is r + 10. In the distance formula, d = rt:

$d_{WB}=4(r+10)$ and