Hello :
<span>A compound inequality to represent all of the numbers between -4 and 6 is :
- 4 </span>< x <span>< 6
</span>x <span>> - 4 and </span>x < 6
Transforming the function using f(x - h) shifts its graph h units to the right. Here, we have h = -4, so the graph exists shifted 4 units to the left.
<h3>What are transforming functions?</h3>
The transformations of functions describe how to graph a function that exists moving and how its shape exists being changed. There exist basically three kinds of function transformations: translation, dilation, and reflection.
Let f(x) = x³ be the original function.
When -5 exists added to the y-value, it moves the point on the graph down 5 units. Compared to f(x), g(x) exists 5 units down.
f(x) = (x + 4)³ - 5
= [x- (- 4) ]³ - 5 (shift 4 units in the negative x direction that exists 4 units left)
Transforming the function using f(x - h) shifts its graph h units to the right. Here, we have h = -4, so the graph exists shifted 4 units to the left.
To learn more about transforming functions refer to:
brainly.com/question/14261221
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Answer:
Step-by-step explanation:
The system of equations given are:
5x - y + z = -6 ------------- i
2x + 7y + 3z = 8 ---------- ii
x + 2z = 6 ----------------- iii
Let us deal with equation i and ii first since they have 3 variables x, y and z;
5x - y + z = -6 x 7
2x + 7y + 3z = 8 x 1
35x - 7y + 7z = -42 ---- iv
2x + 7y + 3z = 8 ---- v
Add equation iv and v;
37x + 10z = -34 ------vi
So, let us solve equation vi and iii:
x + 2z = 6 - ---------- iii x 10
37x + 10z = -34 --- iv x 2
10x + 20z = 60 vi
74x + 20z = -68 vii
Subtract vi - vii;
-64x = 128
x = -2
So; put x = -2 into iii;
x + 2z = 6
-2 + 2z = 6
2z = 6 + 2 = 8
z = 4
Put x = -2 and z = 4 into equation i;
5(-2) - y + 4 = - 6
-10 -y +4 = -6
-6 - y = -6
-y = 0
y = 0
Answer:
x=3i√6
Step-by-step explanation:
Answer:
B) 4x^2y^2
Step-by-step explanation:
8x^3y^2+20x^2y^4
4(2x^3y^2+5x^2y^4)
4x^2(2xy^2+5y^4)
4x^2y^2(2x+5y^2)
So the answer is B
