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Allushta [10]
3 years ago
11

2 1/2 divided by 1 5/8? I forgot how to divide fractions and simplify them....please help

Mathematics
2 answers:
OlgaM077 [116]3 years ago
7 0
2 and a 1/2 = 4/2 + 1/2 = 5/2

1 and 5/8 = 8/8 + 5/8 = 13/8

(5/2)/(13/8)=40/26=20/13=13/13+7/13=1+7/13
nlexa [21]3 years ago
3 0
2\frac{1}{2}:1\frac{5}{8}=\frac{2\times2+1}{2}:\frac{1\times8+5}{8}=\frac{5}{2}:\frac{13}{8}=\frac{5}{\not2_1}\times\frac{\not8^4}{13}=\frac{5}{1}\times\frac{4}{13}=\frac{5\times4}{1\times13}=\frac{20}{13}=1\frac{7}{13}
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Step-by-step explanation:

5 0
3 years ago
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7 0
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Can someone Plzzz help me out???
Vitek1552 [10]

Hello from MrBillDoesMath!


Answer:  3


Discussion:

The perimeter of a polygon is the sum of the side lengths.

Perimeter of top polygon is   (x+2) + 2x + (x + 2) + (4x + 1) =  8x + 5

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6 0
3 years ago
2.02b + 4.30 = 2.00b + 6.30
bonufazy [111]

Answer: b = 100

Step-by-step explanation:

simplifying

2.02b + 4.30 = 2.00b + 6.30

reorder the terms:

4.30 + 2.02b = 2.00b + 6.30

reorder the terms:

4.30 + 2.02b = 6.30 + 2.00b

solving

4.30 + 2.02b = 6.30 + 2.00b

solving for variable 'b'.

move all terms containing b to the left, all other terms to the right.

add '-2.00b' to each side of the equation.

4.30 + 2.02b + -2.00b = 6.30 + 2.00b + -2.00b

combine like terms: 2.02b + -2.00b = 0.02b

4.30 + 0.02b = 6.30 + 2.00b + -2.00b

combine like terms: 2.00b + -2.00b = 0.00

4.30 + 0.02b = 6.30 + 0.00

4.30 + 0.02b = 6.30

add '-4.30' to each side of the equation.

4.30 + -4.30 + 0.02b = 6.30 + -4.30

combine like terms: 4.30 + -4.30 = 0.00

0.00 + 0.02b = 6.30 + -4.30

0.02b = 6.30 + -4.30

combine like terms: 6.30 + -4.30 = 2

0.02b = 2

divide each side by '0.02'.

getting:  b = 100

6 0
3 years ago
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
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