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klemol [59]
3 years ago
13

18. cos t(sec t - cos t)

Mathematics
1 answer:
Margarita [4]3 years ago
8 0
\bf sin^2(\theta)+cos^2(\theta)=1\implies sin^2(\theta)=1-cos^2(\theta)\\\\
sec(\theta)=\cfrac{1}{cos(\theta)}
\\\\
-----------------------------\\\\
cos(t)[sec(t)-cos(t)]\implies cos(t)sec(t)-cos(t)cos(t)
\\\\\\
cos(t)\cdot \cfrac{1}{cos(t)}-cos^2(t)\implies 1-cos^2(t)\implies \boxed{sin^2(t)}
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Solve 2m + 7 = 9
k0ka [10]

Answer:

m=1

Step-by-step explanation:

2m+7=9

subtract 7 on both sides

2m=2

divide 2 on both sides

m=1

hope it helped

8 0
2 years ago
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Choose the correct response​
lilavasa [31]

Answer:

f(2) = 9

Step-by-step explanation:

It's give in the question,

Two different functions are,

f(x) = 4x + 1

g(x) = -2x

Then we have to find the output value of function 'f' for the input value x = 2.

By substituting the value of x in the function 'f',

f(2) = 4(2) + 1

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5 0
2 years ago
There are twice as many students on Mr. Sneed's team as on Mr. Johnson's team. Together, they want to raise 360$ to buy uniforms
KatRina [158]

Answer:

720

Step-by-step explanation:

6 0
2 years ago
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Me ajudem com a 3º questão
Alisiya [41]

I can't read that language but I'll guess it says write a second degree equation then solve for n when d=10.

10 = \dfrac{n(n-3)}{2}

20 = n^2 - 3n

n^2 - 3n - 20 = 0

Answer: n² - 3n - 20 = 0

That doesn't factor so there is no integer n solution.

That means there are no polygons with 10 diagonals.

n = \frac 1 2(3 \pm \sqrt{89})

7 0
2 years ago
If your teacher tells you to do questions 28 through 41 in your math book for homework, how many questions is that?
ANTONII [103]
41-28=13 questions, but you also have to do 41 and 28, so 15 questions
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3 years ago
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