<span>Ex2:Suppose that $5000 is deposited in a saving account at the rate of 6% per year. Find the total amount on deposit at the end of 4 years if the interest is: </span><span> P =$5000, r = 6% , t = 4 years </span><span>a) simple : A = P(1+rt) </span><span>A = 5000(1+(0.06)(4)) = 5000(1.24) = $6200 </span><span>b) compounded annually, n = 1:
</span><span>A = 5000(1 + 0.06/1)(1)(4) = 5000(1.06)(4) = $6312.38 </span><span>c) compounded semiannually, n =2: </span><span>A = 5000(1 + 0.06/2)(2)(4) = 5000(1.03)(8) = $6333.85 </span><span>d) compounded quarterly, n = 4: </span><span> A = 5000(1 + 0.06/4)(4)(4) = 5000(1.015)(16) = $6344.93 </span><span>e) compounded monthly, n =12: </span><span>A = 5000(1 + 0.06/12)(12)(4) = 5000(1.005)(48) = $6352.44
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<span>f) compounded daily, n =365: </span><span>A = 5000(1 + 0.06/365)(365)(4) = 5000(1.00016)(1460) = $6356.12</span>
hope I helped.......................:)
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Answer:
1/12
Step-by-step explanation:
1/4 ÷ 3 = 1/12
Answer:
thank you? i guess...
Step-by-step explanation:
Answer:
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
m∠LOM+m∠MON=m∠LON ----> by angle addition postulate
we have
m∠LOM=2x°
m∠MON=x°
m∠LON=90° ----> is a right angle
substitute the values
solve for x
Answer:
Step-by-step explanation:
x + y = 40
x>y
(11/2)y - (13/4)*x = - 25
x = 40 - y
(11/2)y - (13/4)(40-y) = - 25 multiply by 4
22y - 13( 40 - y) = - 100
22y - 520 + 13y = -400 Add 520
35y = 120
y = 120 / 35
y = 3 3/7
x = 40 - y
x = 36 4/7