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polet [3.4K]
3 years ago
10

Need help ASAP. 1) Determine the volume of the figure that has a radius of 2 feet. Round your answer to the nearest tenth of a c

ubic foot.​

Mathematics
1 answer:
DIA [1.3K]3 years ago
6 0

We have two separate figures here, that have been combined to make one figure. We need to find the volumes of each figure separately, then add them together to find the total volume.

Formula for the volume of a circular cone: V = 1/3 x pi x r^2 x height

Formula for the volume of a cylinder: V = pi x r^2 x height

Solving for the volume of the circular cone:

V = 1/3 x pi x (2)^2 x 3

V = 1/3 x pi x 4 x 3

V = 1/3 x pi x 12

V = 4 x pi

V = 12.5663706144

Solving for the volume of the cylinder:

V = pi x (2)^2 x 10

V = pi x 4 x 10

V = pi x 40

V = 125.663706144

Adding the two volumes together and rounding:

125.663706144 + 12.5663706144 = 138.230076758

V = 138.2 ft^3

Hope this helps!! :)

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b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

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3 years ago
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ASHA 777 [7]

Answer:

15/3

Step-by-step explanation:

.................................

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Natasha_Volkova [10]

Answer:

the first one

Step-by-step explanation:

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What is the answer? Plz help
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Answer:

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Step-by-step explanation:

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