All categories

3 years ago

Mike earned $11.76 per hour for working 23.5 hours last week. how much money did mike earn last week?

Mathematics

1 answer:

densk [106]3 years ago

6 0

Just multiply.

11.76 * 23.5= 276.36

So Mike earned $276.36 last week

You might be interested in

An n-sided polygon has two of its exterior angles measuring 30° and 42°.The remaining exterior angles all measure 16° each. Find

finlep [7]

Answer:

n = 20.

Step-by-step explanation:

The external angles of a polygon add up to 360 degrees. So:

30 + 42 + 16(n - 2) = 360 where n is the number of sides of the polygon.

16n + 30 + 42 - 32 = 360

16n + 40 = 360

16n = 320

n = 20.

5 0

3 years ago

Tickets for an American Baseball League game for 3 adults and 3 children cost less than $75, while tickets for 2 adults and 4 ch

nikitadnepr [17]

<h3>No, the cost of 1 adult ticket cannot be $ 20 and the cost of 1 children ticket is not $ 8.</h3>

Step-by-step explanation:

Let us assume the cots of ticket for 1 adult = $ x

Let us assume the cots of ticket for 1 children = $ y

So, the cost of ticket for 3 adults = 3 x ( Cost of 1 adult ticket) = 3 x

The cost of ticket for 3 children = 3 x ( Cost of 1 children ticket) = 3 y

Also, given the combined cost of 3 adult and children ticket is less than $75.

⇒ 3 x + 3 y < 75 ... (1)

Similarly, the cost of ticket for 2 adults = 2 x

The cost of ticket for 4 children = 4 y

⇒ 2 x + 4 y < 62 ... (2)

Now, solving for the values of x and y, we get:

3 x + 3 y < 75 or, x + y < 25 ⇒ x = 25 - y ( substitute in 2)

2 x + 4 y < 62 or, x + 2 y < 31

⇒ 25 - y + 2 y < 31

or, y + 25 < 31

or, y < 6

⇒ x = 25 - 6 = 19

or, x < 19

So, the cost of 1 adult ticket is x and is less than $19.

The cost of 1 child ticket is y and is less than $6.

Hence, by above statement, NO the cost of 1 adult ticket can not be $ 20 and the cost of 1 children ticket is not $ 8.

4 0

3 years ago

In order to use a ladder safely, the angle that the ladder forms with the ground should not exceed 70 degree. If you have a ladd

solong [7]

Answer:

Maximum safe height can be reached by ladder = 15.03. ft

Step-by-step explanation:

Given,

Let's assume the maximum safe height of wall = h

angle formed between ladder and ground = 70°

length of ladder = 16 ft

From the given data, it can be seen that ladder will form a right angle triangle structure with the wall

So,from the concept of trigonometry,

$Sin70^o\ =\ \dfrac{\textrm{maximum safe height of wall}}{\textrm{length of ladder}}$

$=>Sin70^o\ =\ \dfrac{h}{16\ ft}$

$=>\ h\ =\ 16\times Sin70^o$

=> h = 16 x 0.9396

=> h = 15.03 ft

So, the maximum safe height that can be reached by the ladder will be 15.03 ft.

8 0

3 years ago

Vika [28.1K]

Length of bc is 8
hope this helps :))

3 0

2 years ago

Triangle XYZ has coordinates X(2, 4), Y(−3, 4), and Z(−3, 1). If the triangle is translated using the rule (x, y) → (x − 2, y +

Crank

<span>Y(−3, 4) is the original

</span><span>(x, y) → (x − 2, y + 1) is the rule you're using

(-3, 4) </span>→ (-3 - 2, 4 + 1)

(-3, 4) → (-5, 5)

<span>Y'(–5, 5)</span>

7 0

3 years ago

Read 2 more answers