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Romashka-Z-Leto [24]
3 years ago
13

Mike earned $11.76 per hour for working 23.5 hours last week. how much money did mike earn last week?

Mathematics
1 answer:
densk [106]3 years ago
6 0
Just multiply.

11.76 * 23.5= 276.36

So Mike earned $276.36 last week
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An n-sided polygon has two of its exterior angles measuring 30° and 42°.The remaining exterior angles all measure 16° each. Find
finlep [7]

Answer:

n = 20.

Step-by-step explanation:

The external angles of a polygon add up to 360 degrees. So:

30 + 42 + 16(n - 2)   = 360   where n is the number of sides of the polygon.

16n + 30 + 42 - 32 = 360

16n  + 40 = 360

16n = 320

n = 20.

5 0
3 years ago
Tickets for an American Baseball League game for 3 adults and 3 children cost less than $75, while tickets for 2 adults and 4 ch
nikitadnepr [17]
<h3>No, the cost of 1 adult ticket cannot be $ 20 and the cost of 1 children ticket is not $ 8.</h3>

Step-by-step explanation:

Let us assume the cots of ticket for 1 adult  = $ x

Let us assume the cots of ticket for 1 children  = $ y

So, the cost of ticket for 3 adults = 3 x ( Cost of 1 adult ticket) =  3 x

The cost of ticket for 3 children  = 3 x ( Cost of 1 children ticket)  =  3 y

Also, given the combined cost of 3 adult and children ticket is less than $75.

⇒  3 x +  3  y < 75  ... (1)

Similarly,  the cost of ticket for 2 adults = 2 x

The cost of ticket for 4 children   = 4 y

⇒  2 x +  4  y < 62  ... (2)

Now, solving for the values of x and y, we get:

3 x + 3 y < 75 or, x + y < 25   ⇒ x = 25 - y ( substitute in 2)

2 x +  4  y < 62  or, x +  2 y < 31

⇒   25  - y + 2 y < 31

or, y + 25 < 31

or, y < 6

⇒ x = 25 - 6  = 19

or, x < 19

So, the cost of 1 adult ticket  is x and is less than $19.

The cost of 1 child ticket  is y  and is less than $6.

Hence, by above statement, NO the cost of 1 adult ticket  can not be $ 20 and the cost of 1 children ticket is not $ 8.

4 0
3 years ago
In order to use a ladder safely, the angle that the ladder forms with the ground should not exceed 70 degree. If you have a ladd
solong [7]

Answer:

Maximum safe height can be reached by ladder = 15.03. ft

Step-by-step explanation:

Given,

Let's assume the maximum safe height of wall = h

angle formed between ladder and ground = 70°

length of ladder = 16 ft

From the given data, it can be seen that ladder will form a right angle triangle structure with the wall

So,from the concept of trigonometry,

Sin70^o\ =\ \dfrac{\textrm{maximum safe height of wall}}{\textrm{length of ladder}}

=>Sin70^o\ =\ \dfrac{h}{16\ ft}

=>\ h\ =\ 16\times Sin70^o

=> h = 16 x 0.9396

=> h = 15.03 ft

So, the maximum safe height that can be reached by the ladder will be 15.03 ft.

8 0
3 years ago
4.
Vika [28.1K]
Length of bc is 8
hope this helps :))
3 0
2 years ago
Triangle XYZ has coordinates X(2, 4), Y(−3, 4), and Z(−3, 1). If the triangle is translated using the rule (x, y) → (x − 2, y +
Crank
<span>Y(−3, 4) is the original

</span><span>(x, y) → (x − 2, y + 1) is the rule you're using

(-3, 4) </span>→ (-3 - 2, 4 + 1)

(-3, 4) → (-5, 5)

<span>Y'(–5, 5)</span>
7 0
3 years ago
Read 2 more answers
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