Answer:
SEE THE IMAGE ABOVE FOR ANSWER.
6.7 10 squared positive 8
We are asked to find the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34.
The probability of a data score between two z-scores is given by formula
.
Using above formula, we will get:
![P(-1.32](https://tex.z-dn.net/?f=P%28-1.32%3Cz%3C-0.34%29%3DP%28z%3C-0.34%29-P%28z%3C-1.32%29)
Now we will use normal distribution table to find probability corresponding to both z-scores as:
![P(-1.32](https://tex.z-dn.net/?f=P%28-1.32%3Cz%3C-0.34%29%3D0.36693-0.09342)
![P(-1.32](https://tex.z-dn.net/?f=P%28-1.32%3Cz%3C-0.34%29%3D0.27351)
Now we will convert
into percentage as:
![0.27351\times 100\%=27.351\%](https://tex.z-dn.net/?f=0.27351%5Ctimes%20100%5C%25%3D27.351%5C%25)
Upon rounding to nearest tenth of percent, we will get:
![27.351\%\approx 27.4\%](https://tex.z-dn.net/?f=27.351%5C%25%5Capprox%2027.4%5C%25)
Therefore, our required probability is 27.4% and option C is the correct choice.
good morning,
Answer:
10×(1-0.2ⁿ)
Step-by-step explanation:
1.6/8=0.2
0.32/1.6=0.2
0.064/0.32=0.2
let S represent the sum of n term then S=8×[(1-0.2ⁿ)/(1-0.2)] = 10×(1-0.2ⁿ).
:)