In the first case we'd subtract 1 from both sides, obtaining |x-1|<14.
In the second case we'd also subtract 1 from both sides, and would obtain
|x-1|>14.
What would the graphs look like?
In the first case, the graph would be on the x-axis with "center" at x=1. From this center count 14 units to the right, and then place a circle around that location (which would be at x=15). Next, count 14 units to the left of this center, and place a circle around that location (which would be -13). Draw a line segment connecting the two circles. Notice that all of the solutions are between -13 and +15, not including these endpoints.
In the second case, x has to be greater than 15 or less than -13. Draw an arrow from x=1 to the left, and then draw a separate arrow from 15 to the right. None of the values in between are solutions.
Answer:
I would have to say C.14
Step-by-step explanation:
Because if you are running the same exact emperiment with the same exact materials everytime then you should get the same outcome.
Hope this helps! : D
Answer:
x > 15
Step-by-step explanation:
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Hello,
After a long division:
8x^3+5x^2-12x+10=(x^2-3)(8x+5)+12x+25
